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8090 [49]
3 years ago
6

Stan is colorblind, but otherwise has normal visual acuity-whats the most likely cause of this?

Biology
1 answer:
san4es73 [151]3 years ago
7 0
The photoreceptor inside retina is the receptor of light that makes an organism capable to see. The photoreceptor consists of cone cells that can distinguish color and rod cells that can distinguish color as black and white image.

There are three kinds of cone cells, red, green and blue. The interaction of stimulus given by these 3 kinds of cone cells gives the perception of color. In color-blind patient, some of the cone cells are damaged or not formed. Losing the cone cells will cause color blind patient unable to perceive color. To have a good visual acuity, you don't need all the cone cells variety, only one kind is enough.
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Which diet instructions are appropriate when teaching a client in the early stages of cirrhosis about nutritional needs? select
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8 0
4 years ago
. Given that 3 of the 64 possible codons are stop codons, what is the chance of having a stop codon at any given position, assum
ANTONII [103]

Answer:

1 - (\frac{61}{64})^n

Explanation:

Given

There are three stop codon

TAA, TAG, TGA.

Out of 64 available codons, 3 are stop codon thus the remaining are non-stop codon.

So the probability of choosing a non stop codon is

\frac{61}{64}

Let us suppose the number of trials are "x" then the probability of choosing a non stop codon is  

(\frac{61}{64})^x\\

Probability of choosing a stop codon is equal to

1 - probability of choosing a non stop codon

1 - (\frac{61}{64})^n

4 0
3 years ago
Phases of meiosis on the lines provided, identify the stage of meiosis i or meiosis ii in which the event described occurs. 9. e
Natalka [10]
Meiosis I
Prophase I - homologous chromosomes form a tetrad, where they begin cross-over through the process of synapses.
Metaphase - homologous chromosomes then align along the metaphase plate.
Anaphase I - spindles then separate the homologous chromoses, pulling them to opposite poles of the cell
Telephase I - the cell creates a cleavage burrow inwhich the cell divides into two new cells with 46 chromosomes in the process of cytokinesis

Meiosis II
The same as mitosis
Prophase II - Nuclear envelope disintegrates, Sister chromatids migrate towards the metaphase plate.
Metaphase II - Sister chromatids align along the plate by their centromere.
Anaphase II- spindles pull the chromatin to opposites poles
Telephase II- cleavage burrow forms and cells seperate through cytokinesis

end result
4 haploid gametes are formed
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Answer:

the correct answer is c

6 0
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Question 1 - 100%

* I need to know what the crosses are for questions 2-5

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