Answer:
13 pieces
Step-by-step explanation:
Trust me.
1427 = (F) (+ F + 60) (2F - 50) (+ 3F)
<em>Each pair of brackets represents one of the classes - F meaning Freshmen Class. It has been split into brackets for demonstrational purposes - nothing is being multiplied.</em>
F is an unknown number and each other class size is based off of that so we put it in algebraic terms in order to work it out.
1 - Freshmen Class
2 - Sophomore Class (Freshmen Class + 60 more students)
3 - Junior Class ( Twice the size of the Freshmen Class - 50 students)
4 - Senior Class (Three times the size of the Freshmen Class)
All this can be simplified to 7F + 10 = 1427
1427 - 10 = 1417
1417/7 = 202.428....
Is there a mistake in the question?
Following the question with 202 as the answer - the number 1424 is reached
If increased to 203 - 1431 is reached.
The answer shouldn't include half a person.
First of 3/7 of a week is 3 days because there are 7 days in a week e out of seven so you get it?
1. The question is asking you how much barrels of raisins is used in three days but first you need to find out how much they use in 1 day (this is how I would do it) so turn all the fractions into a decimal
4/9 = 0.4444...
6/5= 1.20
3/7= 0.43
So now you got your decimals
2. Multiply 0.4444 by 1.20 now you got how much you get a day for cosmos bakery which is 0.53
3. Now go back to the 3/7 of a week which is 3 days and now you need to multiply 0.53 by 3 and you will get your answer
ANSWER!
1.59 a day for cosmos bakery
I HOPE THIS HELPED YOU TO SOLVE THIS PROBLEM AND SOME FUTURE ONES!
Answer:
$7,987.64
Step-by-step explanation:
We know,
A = Pe^(rt)
Here,
A = 11000
interest r = .08
Time t = 4
Now,
11000 = Pe^(.08 * 4)
Or, 11000 = Pe^.32
Or, 11000 / e^.32 = P
Or, 7987.6394 = P
Or, P= 7,987.64
Jerome will have to ask for $7,987.64 to his parents.
Let the required point be (a,b)
The distance of (a,b) from (7,-2) is
= 
But this distance needs to be betweem 50 & 60
So
Squaring all sides
2500 < (a-7)² + (b+2)² < 3600
Let a = 7
So we have
2500 < (b+2)² <3600
b+2 < 60 or b+2 > -60 => b <58 or b > -62
Also
b+2 >50 or b + 2 < -50 => b >48 or B < -52
Let us take one value of b < 58 say b = 50
So now we have the point as (7, 50)
The other point is (7,-2)
Distance between them
= 
This is between 50 & 60
Hence one point which has a distance between 50 & 60 from the point (7,-2) is (7, 50)
