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Leviafan [203]
3 years ago
11

Simplify: The square root of p squared

Mathematics
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer:

p

Step-by-step explanation:

\sqrt{p^2} = p

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The means and mean absolute deviations of the amount of rain that fell each day in a local city, last week and this week, are sh
jekas [21]

Answer:

0.8 / 0.5

Step-by-step explanation:

Given :

Deviations of Rainfall :

______Last Week ____ This Week

Mean___ 3.5 in. ________2.7 in

MAD ___ 1.2 in _________ 0.5 in

Mean difference = 3.5 in - 2.7 in = 0.8 in

This week's mean absolute deviation = 0.5 in

Mean difference / this week's mean absolute deviation

= 0.8 / 0.5

8 0
3 years ago
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Math question help need it​
Lelechka [254]

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Dont really understand what the question is saying but i graphed it on Desmos hope this helps

Step-by-step explanation:

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How do you round 1866.025404 to the nearest centimetre? Please explain.
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Answer:

1866

Step-by-step explanation:

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Lapatulllka [165]
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4 years ago
Differentiate 4^xlnx
Vsevolod [243]

If you mean

\dfrac{\mathrm d}{\mathrm dx}\left[4^x\ln(x)\right]

then first write 4^x=e^{\ln(4^x)}=e^{\ln(4)x}. Then by the product rule,

\dfrac{\mathrm d}{\mathrm dx}\left[4^x\ln(x)\right] = \ln(4)e^{\ln(4)x}\ln(x) + \dfrac{e^{\ln(4)x}}x = \ln(4)4^x\ln(x)+\dfrac{4^x}x=\dfrac{4^x}x\left(\ln(4)x\ln(x)+1\right)

If you instead mean

\dfrac{\mathrm d}{\mathrm dx}\left[4^{x\ln(x)}\right]

you can again rewrite 4^{x\ln(x)} = e^{\ln\left(4^{x\ln(x)}\right)}=e^{x\ln(x)\ln(4)}. Then by the chain and product rules,

\dfrac{\mathrm d}{\mathrm dx}\left[4^{x\ln(x)}\right] = e^{x\ln(x)\ln(4)}\ln(4)\left(\ln(x)+1\right) = 4^{x\ln(x)}\ln(4)(\ln(x)+1)

8 0
3 years ago
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