Answer:
As the lines are not intersecting nor parallel, they must be skew.
Step-by-step explanation:
Question is incomplete, we consider the nearest match available online.
Parametric equations of two lines are:
L₁ : x=4t+2 , y = 3 , z =-t+1
L₂: x=2s+2 , y= 2s+5 , z = s+1
If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.
If lines are intersecting then parametric coordinates must be equal for some value of t and s.
Hence the lines are not intersecting nor parallel, they must be skew.
Answer:
c = 1 , a = 2, b = 3
Step-by-step explanation:
Answer:
We have been given an equation
We will factorize it by middle term splitting.
Step 1:
Taking common factors out by clubing first two terms ad last two terms
Step 2:
Step 3:
Equating both above factors to zero as:
Step 4:
And .
4x-6y = 12
Add 6y to both sides
4x = 12 + 6y
Subtract 12 on both sides
4x - 12 = 6y
Divide 6 on both sides
y = 2/3 x - 2
Next equation
-2x + 3y = -6
Add 2x to both sides
3y = 2x - 6
Divide 3 on both sides
y = 2/3x - 2