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kobusy [5.1K]
3 years ago
11

You are searching for two integers. The sum of twice the first integer and three times the second integer is nine. At the same t

ime, the sum of three times the first integer and twice the second integer is one. Find the two integers.
Mathematics
1 answer:
devlian [24]3 years ago
4 0

Answer:  -3 and 5

<u>Step-by-step explanation:</u>

Let x represent the 1st digit and y represent the 2nd digit. Then,

Eq 1: 2x + 3y = 9   →    3(2x + 3y = 9)     →     6x + 9y = 27

Eq 2: 3x + 2y = 1   →   -2(3x + 2y = 1)     →     <u>-6x - 4y =  -2</u>

                                                                              5y = 25

                                                                                y =  5

Substitute y = 5 into either of the original equations to solve for x:

2x + 3y = 9

2x + 3(5) = 9

2x + 15 = 9

2x        = -6

 x        = -3

Check (using the other original equation):

3x + 2y = 1

3(-3) + 2(5) = 1

-9    +  10   = 1

        -1       = 1  \checkmark

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