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Nadya [2.5K]
3 years ago
12

What is the solution of square root of-4x=100? x = –2500 x = –50 x = –2.5 no solution

Mathematics
1 answer:
alex41 [277]3 years ago
4 0
√(-4x) = 100
-4x = 100² = 10,000
x = 10,000/-4 = -2500

The solution is ...
  x = -2500
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natulia [17]

Answer:

4y²-1/4 is the required answer

Step-by-step explanation:

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Please help with this precalc!!! i desperately need help
Paladinen [302]

Step-by-step explanation:

4 is the A or Ampltiude

To find the period set it equal to 2 pi/B

\frac{2\pi}{b}  =  \frac{6}{1}

\frac{b}{2\pi}  =  \frac{1}{6}

b=

\frac{2\pi}{6}

b=

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There is no phase shift

The midline or d or vertical shift is 1.

Our equation for 8 is

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\frac{b}{2\pi}  =  \frac{3}{\pi}

b =  \frac{3}{\pi}  \times 2\pi

Which equal 6.

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6 0
3 years ago
What is the the slope that passes through the points (4,-7) and (9,1)
bulgar [2K]

Answer:

8/5

Step-by-step explanation:

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Read 2 more answers
The screening process for detecting a rare disease is not perfect. Researchers have developed a blood test that is considered fa
lesya692 [45]

Answer:

Type I: 1.9%, Type II: 1.6%

Step-by-step explanation:

given null hypothesis

H0=the individual has not taken steroids.

type 1 error-falsely rejecting the null hypothesis

⇒   actually the null hypothesis is true⇒the individual has not taken steroids.

 but we rejected it ⇒our prediction is the individual has taken steroids.

typr II error- not rejecting null hypothesis when it has to be rejected

⇒actually null hypothesis is false ⇒the individual has taken steroids.

but we didnt reject⇒the individual has not taken steroids.

let us denote

the individual has taken steroids by 1

the individual has not  taken steroids.by 0

                            predicted

                              1       0

   actual          1    98.4%  1.6%

                        0   1.9%   98.1%

so for type 1 error  

 actual-0

predicted-1

therefore from above table we can see that probability of Type I error is 1.9%=0.019

so for type II error

   actual-1

predicted-0

therefore from above table we can see that probability of Type I error is 1.6%=0.016

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3 years ago
32​% of college students say they use credit cards because of the rewards program. You randomly select 10 college students and a
Tems11 [23]

Answer:

a) P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

b) P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

c) P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=10, p=0.32)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

Part b

P(X> 2)=1-P(X\leq 2)=1-[P(X=0)+P(X=1)+P(X=2)]

P(X=0)=(10C0)(0.32)^0 (1-0.32)^{10-0}=0.0211  

P(X=1)=(10C1)(0.32)^1 (1-0.32)^{10-1}=0.0995

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X> 2)=1-P(X\leq 2)=1-[0.0211+0.0995+0.211]=0.668

Part c

P(2 \leq x \leq 5)=P(X=2)+P(X=3)+P(X=4)+P(X=5)

P(X=2)=(10C2)(0.32)^2 (1-0.32)^{10-2}=0.211

P(X=3)=(10C3)(0.32)^3 (1-0.32)^{10-3}=0.264

P(X=4)=(10C4)(0.32)^4 (1-0.32)^{10-4}=0.218

P(X=5)=(10C5)(0.32)^5 (1-0.32)^{10-5}=0.123

P(2 \leq x \leq 5)=0.211+0.264+0.218+0.123=0.816

6 0
3 years ago
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