All categories

3 years ago

In the diagram below, angle 7 equals 61°. What is the measure of angle 8?

Mathematics

2 answers:

V125BC [204]3 years ago

7 0

Answer:

119

Step-by-step explanation:

So angle 6 equals angle 7 vertically opp angles. So 61 times 2 is 122. Total angles around a point is 360. So 360 - 122 is 238 which divided by 2 will give 119 cause angle 8 equals angle 5.

ella [17]3 years ago

3 0

Answer: 119 degrees

Step-by-step explanation: Since the angles 6 and 7 are both 61 degrees, multiply by 2 and you get 122. Then subtract 122 from 360 to get 238 degrees. Then divide 238 by 2 to get 119 degrees.

(I tried)

You might be interested in

MANY PTS AND BRAINLY FAST

Troyanec [42]

Answer:

Option C

Step-by-step explanation:

we have

$-6x^{2} -6x+12=0$

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$-6x^{2} -6x=-12$

step 2

Factor -6 leading coefficient'

$-6(x^{2} +x)=-12$

step 3

Complete the square

Remember to balance the equation by adding the same constants to each side

$-6(x^{2} +x+0.25)=-12-1.5$

$-6(x^{2} +x+0.25)=-13.5$

step 4

Rewrite as perfect squares

$-6(x+0.5)^{2}=-13.5$

simplify

$(x+0.5)^{2}=2.25$

5 0

3 years ago

Read 2 more answers

NEED URGENT HELP!! WILL GIVE BRAINLIEST

Flauer [41]

1. You need to multiply the denominator by something that will make the content of the radical be a square—so that when you take the square root, you get something rational. Easiest and best is to multiply by √6. Of course, you must multiply the numerator by the same thing. Then simplify.

$\displaystyle\frac{2}{\sqrt{6}}=\frac{2}{\sqrt{6}}\cdot\frac{\sqrt{6}}{\sqrt{6}}\\\\=\frac{2\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\frac{2\sqrt{6}}{6}\\\\=\bf{\frac{\sqrt{6}}{3}}$

2. Identify the squares under the radical and remove them.

$5\sqrt{12xm^3}=5\sqrt{(4m^2)(3xm)}=5\sqrt{(2m)^2}\sqrt{3xm}\\\\=5\cdot 2m\sqrt{3xm}=\bf{10m\sqrt{3xm}}$

7 0

3 years ago

Read 2 more answers

Find the quotient −40÷20.

sukhopar [10]

Answer:

-2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

3 years ago

X equals ??????????

Ymorist [56]

Answer: x = 18

explanation: the two angles are congruent bc so you can set the equation up as 9x - 40 = 5x + 32 and then solve for x

hope this helps :)

7 0

3 years ago