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lara [203]
3 years ago
9

In the diagram below, angle 7 equals 61°. What is the measure of angle 8?

Mathematics
2 answers:
V125BC [204]3 years ago
7 0

Answer:

119

Step-by-step explanation:

So angle 6 equals angle 7 vertically opp angles. So 61 times 2 is 122. Total angles around a point is 360. So 360 - 122 is 238 which divided by 2 will give 119 cause angle 8 equals angle 5.

ella [17]3 years ago
3 0

Answer: 119 degrees

Step-by-step explanation: Since the angles 6 and 7 are both 61 degrees, multiply by 2 and you get 122. Then subtract 122 from 360 to get 238 degrees. Then divide 238 by 2 to get 119 degrees.

(I tried)

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Answer:

Option C

Step-by-step explanation:

we have

-6x^{2} -6x+12=0

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

-6x^{2} -6x=-12

step 2

Factor -6 leading coefficient'

-6(x^{2} +x)=-12

step 3

Complete the square

Remember to balance the equation by adding the same constants to each side

-6(x^{2} +x+0.25)=-12-1.5

-6(x^{2} +x+0.25)=-13.5

step 4

Rewrite as perfect squares

-6(x+0.5)^{2}=-13.5

simplify

(x+0.5)^{2}=2.25

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Flauer [41]

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\displaystyle\frac{2}{\sqrt{6}}=\frac{2}{\sqrt{6}}\cdot\frac{\sqrt{6}}{\sqrt{6}}\\\\=\frac{2\sqrt{6}}{\sqrt{6}\cdot\sqrt{6}}=\frac{2\sqrt{6}}{6}\\\\=\bf{\frac{\sqrt{6}}{3}}

2. Identify the squares under the radical and remove them.

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Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt
tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

f(x)= \sqrt{\dfrac{x+1}{x-1}}

g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

\dfrac{x+1}{x-1}>0

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

x+1\leq 0\Rightarrow x\leq -1

x-1\leq 0\Rightarrow x\leq 1

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

x+1\geq 0\Rightarrow x\geq -1

x-1\geq 0\Rightarrow x\geq 1

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

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3 years ago
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Ymorist [56]
Answer: x = 18

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