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iVinArrow [24]
3 years ago
9

A golf ball and bowling ball are moving and both have the same kinetic energy.Which one is moving faster? If they move at the sa

me speed, which one has more kinetic energy?
Please help me :(
Chemistry
1 answer:
joja [24]3 years ago
5 0
I believe the answer to the first question is the golf ball because it requires less energy to move it so it will move faster than the bowling ball will with less energy. For the second question I could be wrong but I think the bowling ball has more kinetic energy because according to the equation KE= 0.5*m* x^{2} where KE represents the kinetic energy the m is the mass and x is the speed of the object the bowling ball will have more energy.
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taurus [48]

Solution us here,

let the rate of diffusion of H2(r1) be x and⁷ the rate of diffusion of gas(r2) be x+x/6=7x/6.

Molar mass of H2 (M1)=2 g

Molar mass of gas(M2)= ?

Now, from the Ghram's law of diffusion of gas,

\frac{r1}{r2}  =   \sqrt{ \frac{m2}{m1}  }   \\ or \:  \frac{x}{ \frac{7x}{6} }  =  \sqrt{ \frac{m2}{2} }  \\ or \:  \frac{6}{7}  =  \sqrt{ \frac{m2}{2} }  \\ squaring \: in \: both \: sides \\  \frac{36}{49}  = \frac{m2}{2}  \\ or m2 = 1 .469

here, it looks like I have done wrong.

But all of the answers in option are wrong.

Because, rate of diffusion of any gas is inversely proportional to the square root of its malor mass.

And in the question, gas has higher rate of diffusion than hrdrogen. So it should have molar mass less than hydrogen.

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4 years ago
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USPshnik [31]

Answer:

The volume is

<h2>180 mL</h2>

Explanation:

In order to solve for the volume we use the formula for Boyle's law which is

<h3>P _{1}  V _{1} = P _{2}V _{2}</h3>

where

P1 is the initial pressure

V1 is the initial volume

P2 is the final pressure

V2 is the final volume

Since we are finding the final volume we are finding V2

Making V2 the subject we have

<h3>V _{2}  = \frac{P _{1}  V _{1}}{P _{2}  }</h3>

From the question

P1 = 300 mmHg

V1 = 300 mL

P2 = 500 mmHg

Substitute the values into the above formula and solve for the final volume obtained

That's

<h3>V _{2} =  \frac{300 \times 300}{500}  \\  =  \frac{90000}{500}  \\  =  \frac{900}{5}</h3>

We have the final answer as

<h3>180 mL</h3>

Hope this helps you

7 0
4 years ago
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It's rearranged to time as, time=\frac{distance}{speed}

Let's plug in the values in it:

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here we can explain by using the example.

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again,

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