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ivanzaharov [21]
3 years ago
7

Do anyone idc just please I need help!!!!

Mathematics
1 answer:
aalyn [17]3 years ago
3 0
I did a few, to show you how.
Slide 1:
A) class A; range of 7
B) class a; 5.5
C) class b; 6.7 appx
D) class a

These are how to find each one:

Mean: add all the numbers and divide by the number of numbers. Ex. 1+2+3= 6/3=2
Median: middle of the numbers
Range: take the smallest value away from the largest value
IQR: find the median; find the range of the numbers above and below the median. Take the range of those two numbers that is the IQR
MAD: find the mean; take absolute value of numbers and subtract mean (|x|-mean); find sum of absolute value and difference; divide by the number of numbers.

You might be interested in
When buying an object on sale, the _______ is the decrease in the price of the item.
telo118 [61]

Answer:

I think that the answer is 'sale'.

Step-by-step explanation:

5 0
3 years ago
1. A notebook costs $5 more than a folder. Greg purchased 3 notebooks and 2 folders and paid a total cost $30. What is the cost
stiv31 [10]
Answer
Notebook each =$4
Folder each = $9

First we write out what we know
Notebook = n
Folder = f
It says a notebook is +5 than a folder so
f = n +5
It says he bought 3 notebooks and 2 folders for $30
3n + 2f = 30

Because we know from the first equation
f=n+5, we can substitute that into the second equation for f

3n + 2(n+5) = 30
3n + 2n +10 =30. Now Combine like terms
5n +10 =30. Now isolate n by subtracting 10 from both sides
5n = 20. Now isolate n by dividing both sides by 5
n = 4

Now we do the same thing to find f
We substitute the value of n (4) into the equation 3n + 2f =30
3(4) +2f =30
12 +2f =30. Now isolate f by subtracting 12 from both sides
2f = 18. Now isolate f by dividing both sides by 2
f = 9


We check our work by inserting the n and f values we found into one of the equations
n + 5 = f
4 + 5 = 9
9 = 9. It worked it equals so it’s correct
8 0
1 year ago
<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2
Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

but the integrand is even, so this is really just

\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx

Substitute x = 1/2 arccot(u/2), which transforms the integral to

\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du

There are lots of ways to compute this. What I did was to consider the complex contour integral

\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}

which vanishes as R goes to ∞. Then by the residue theorem, we have in the limit

\displaystyle \int_{-\infty}^\infty \frac{\cos(x)}{x^2+4} \, dx = 2\pi i {} \mathrm{Res}\left(\frac{e^{iz}}{z^2+4},z=2i\right) = \frac\pi{2e^2}

and it follows that

\displaystyle \int_0^\pi \cos(\cot(x)-\tan(x)) \, dx = \boxed{\frac\pi{e^2}}

7 0
1 year ago
NO LINKS I WILL REPORT!!! But help PLSS It's possible to build a triangle with side lengths of 5, 7, and 11.
strojnjashka [21]

Answer:

yes it is possible

I hope it's helps you

8 0
3 years ago
Read 2 more answers
How do I solve for the missing numbers
Veronika [31]

Answer:

going from left to right: 200, 400, 800

Step-by-step explanation:

25 x 2 = 50

50 x 2 = 100

100 x 2 = 200

200 x 2 = 400

400 x 2 = 800

just follow the pattern

4 0
2 years ago
Read 2 more answers
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