What’s the answer plz!!
2 answers:
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Answer:
a) P(E|F) = 0.5
b) P(F|E) = 0.167
c) P(E|F') = 0.625
d) P(E′|F′) = 0.375
Step-by-step explanation:
P(E) = 0.6
P(F) = 0.2
P(E n F) = 0.1
a) P(E|F) = Probability of E occurring, given F has already occurred. It is given mathematically as
P(E|F) = [P(E n F)]/P(F) = 0.1/0.2 = 0.5
b) P(F|E) = Probability of F occurring, given E has already occurred. It is given mathematically as
P(F|E) = [P(E n F)]/P(E) = 0.1/0.6 = 0.167
c) P(E|F′) = Probability of E occurring, given F did not occur. It is given mathematically as
P(E|F') = [P(E n F')]/P(F')
But P(F') = 1 - P(F) = 1 - 0.2 = 0.8
P(E n F') = P(E) - P(E n F) = 0.6 - 0.1 = 0.5
P(E|F') = 0.5/0.8 = 0.625
d) P(E′|F′) = [P(E' n F')]/P(F')
P(F') = 0.8, P(Universal set) = P(U) = 1
P(E' n F') = P(U) - [P(E n F') + P(E' n F) + P(E n F) = 1 - (0.5 + 0.1 + 0.1) = 0.3
P(E′|F′) = 0.3/0.8 = 0.375
Answer:
The probability of a chain defect is 3%.
Step-by-step explanation:
Given : A bicycle manufacturer is studying the reliability of one of its models. The study finds that the probability of a brake defect is 4 percent and the probability of both a brake defect and a chain defect is 1 percent.
If the probability of a defect with the brakes or the chain is 6 percent
To find : What is the probability of a chain defect?
Solution :
Let A be the event of brake defect
and B be the event of chain defect.
We have given, P(A)= 4%=0.04
P(A and B) = 1%=0.01
P(A or B)= 6%=0.06
We have to find P(B),
The formula used is,
Substitute the value,
or
Therefore, The probability of a chain defect is 3%.