7+13+1.5=21.5
If he did it again the way back, it's 21.5 times 2.
He went a total of 43 blocks.
12. hope that helps you with your homework
Answer:
Step-by-step explanation:
<u> 4km</u>
*
* 
4km ÷ 10.73 km/hr = .37 hr = 22.3 minutes
Answer:
It would take approximately 6.50 second for the cannonball to strike the ground.
Step-by-step explanation:
Consider the provided function.

We need to find the time takes for the cannonball to strike the ground.
Substitute h(t) = 0 in above function.

Multiply both sides by 10.

For a quadratic equation of the form
the solutions are: 
Substitute a = -49, b = 305 and c=88

Ignore the negative value of t as time can't be a negative number.
Thus,

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.
5 peaces and 5 blueberry packages 0.75*5=3.75. 1.50*5=7.5. 3.75+7.5=11.25