15) 5,25 , 125 ,625 ,3125Rule =

Mathematics

1 answer:

MrMuchimi3 years ago

4 0

Answer:

multiply by 5

Step-by-step explanation:

5x5=25

25x5+125

125x5=625

You might be interested in

If your salary is $42,500 and your federal income taxes are 10% of your salary, how much money will you owe this year in federal

Zarrin [17]

I'm assuming that the salary is for the whole year. If it is not, do tell me.
Tax = 10/100 * 45000
= 4500
You owe $4500 in federal taxes.

6 0

3 years ago

Starting at time t = 0, the altitude of one helicopter is given by A1 = 600 + 150t, and the altitude of a second helicopter is g

Soloha48 [4]

Answer:

The equation for difference in altitude of the two helicopters is A = 650 - 100t

Step-by-step explanation:

Given;

The altitude of one helicopter is, A1 = 600 + 150t

The altitude of a second helicopter is, A2 = 1250 + 50t

Their difference in altitude, A at time t, is calculated as

A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)

A₂ - A₁ = A = 1250 + 50t - 600 -150t

A₂ - A₁ = A = 1250 - 600 + 50t - 150t

A₂ - A₁ = A = 650 - 100t

Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t

3 0

3 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$