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3 years ago

If y = 3x+b intersects y= mx +3 at (2, 3), find the value of b and m.

Mathematics

2 answers:

Darina [25.2K]3 years ago

3 0

Answer:

The value of b is -3 and m is 0.

Step-by-step explanation:

You have to substitute the coordinates into both equation in order to find m and b value :

Find m,

$y = mx + 3$

At (2,3),

$3 = m(2) + 3$

$3 - 3 = 2m$

$2m = 0$

$m = 0$

Find b,

$y = 3x + b$

At (2,3),

$3 = 3(2) + b$

$b + 6 = 3$

$b = 3 - 6$

$b = - 3$

Zanzabum3 years ago

3 0

Answer:

b = -3

m = 0

Step-by-step explanation:

y=mx+b

3 is the constant

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5 0

3 years ago

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vodomira [7]

Answer:

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Step-by-step explanation:

Given :

Area of square = Area of the rectangle

According to the question:

Length of the square be 'x'.

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Length of the rectangle = $(x+4)$

Width of the rectangle = $(x-2)$

Area of the rectangle =Length * Width

⇒ $(x+4)(x-2)=x^2-2x+4x-8$

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Equating both the equation as area of both the figure are equal.

⇒ $x^2+2x-8=x^2$

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