Question

What is the equation of the line, in point slope form, that passes through the given point and has the given slope?

Answer 1

The point-slope form:

$y-y_1=m(x-x_1)$

We have the point (11, 3) and the slope m = 4/11. Substitute:

$\boxed{y-3=\dfrac{4}{11}(x-11)}$

Answer 2

Answer:

$y=\frac{4}{11}x-1$

Step-by-step explanation:

To find the equation, we have to use the point-slope formula:

$y-y_{1}=m(x-x_{1})$

Where $m$ is the slope and $(x_{1};y_{1})$ is the points through the line passes.

So, from the problem we have:

$m=\frac{4}{11}$

$(11,3)$

Replacing these elements, we have:

$y-3=\frac{4}{11}(x-11)\\ y=\frac{4}{11}x-4+3\\ y=\frac{4}{11}x-1$

Therefore, the equations is

$y=\frac{4}{11}x-1$