<h2>Answer:</h2><h2>x=3 </h2><h2>p=3csc (β)sec(θ)</h2><h2>hope this helps! ;)</h2>
Answer:
Non-mutually exclusive
Step-by-step explanation:
both events can happen simultaneously... 3 is an odd number, events A and B have a common outcome.
It would be mutually exclusive if event A was rolling a 4 and event B was rolling an odd number.
<span>The vertex of the parabola is the highest or lowest point of the graph.
</span><span>y=-4x^2+8x-12 = -4 (x^2 -2x +3)
Lets work with this now: </span>x^2 -2x +3
x^2 -2x +3 -> what is the closeset perfect square?
x^2 -2x +1 = (x-1)^2
So
x^2 -2x +3 = (x-1)^2 +2
Replacing to original
y=-4x^2+8x-12 = -4 (x^2 -2x +3) = -4 ((x-1)^2 +2) = -4 (x-1)^2 - 8
The min or max point is where the squared part = 0
So when x=1 , y= -4*0-8=-8
This will be the max of the parabola as there is - for the highest factor (-4x^2)
The max: x=1, y= -8
Answer:
I recoment using the formula because its different ways its taught
Step-by-step explanation:
maybe look up different formula's
Answer:
(3+2)x - 4x
Step-by-step explanation:
I just converted the words, turned them to operations and that's it!
Hope this helps! :D
- Anna
