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gladu [14]
3 years ago
14

The cost of ordering multiple items is sometimes, always or never proportional

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0
Unless there is no promotion like "buy 2 get 1 free" or "buy 2 get 1 for 50%" etc. then the cost of ordering multiple items is always proportional. Let's say something costs $5. Two items will cost $10, three $15, four $20 etc. These numbers are all proportional. Hopefully that's what you meant :)
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Angela ordered 2 glass paperweights. The volume of each paperweight is 5 cubic inches, and the density of the glass is 1.5 ounce
Katarina [22]

Answer:

(2\times 5)\times 1.5

Step-by-step explanation:

Since, according to associative property of multiplication,

a(bc) = (ab)c,

Where a, b and c are any real numbers,

Here, the given expression,

2 × ( 5 × 1.5 ),

By applying the associative property of multiplication,

( 2 × 5 ) × 1.5,

Hence, the appropriate expression in the first box is '(2×5)'

And, the appropriate number in the second box is '1.5'.

8 0
4 years ago
How many eighth notes do you need to total the amount of a half note
andrew11 [14]

Answer:

Four eighth notes

Four eighth notes equal one half note in duration and eight eighth notes equal one whole note.

Step-by-step explanation:

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8 0
3 years ago
Ask your teacher find the limit. use l'hospital's rule where appropriate. if there is a more elementary method, consider using i
liberstina [14]

Answer:

  ln(5/3)

Step-by-step explanation:

The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.

<h3>Limit</h3>

We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.

  \diplaystyle \lim\limits_{x\to1}{(\ln(x^5-1)-\ln(x^3-1))}=\lim\limits_{x\to1}\ln{\left(\dfrac{x^5-1}{x^3-1}\right)}\\\\=\lim\limits_{x\to1}\ln\left(\dfrac{x^4+x^3+x^2+x+1}{x^2+x+1}\right)=\ln{\dfrac{5}{3}}

8 0
1 year ago
There are two red jars of marbles and one blue jar of marbles jars of a certain color have the same number of marbles in them. T
satela [25.4K]
We can set up an equation to solve this problem.  I am setting the number of marbles in a red jar to R.

R + R + R - 16 = 41

We solve this by adding 16 to both sides and combining all of the R terms..  This gives us:

3R = 57

We can finish this problem by dividing both sides by 3.

R = 19.  So, there are 19 marbles in a red jar.

We can easily figure out how many marbles are in a blue jar by subtracting the total amount of marbles in 2 red jars from the total amount of marbles.  I am setting the amount of marbles in a blue jar to B.

41 - 19*2 = B

B = 3

So, there are 3 marbles in a blue jar and 19 marbles in a red jar.



7 0
3 years ago
What is 8(5x - 3y)=
Monica [59]

Answer:

40x-24y

You simplify through distribution

4 0
3 years ago
Read 2 more answers
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