Answer:
2 moles NH3 = 1 mole of N2
3 moles of H2 = 1 mole of N2
3 moles of H2 = 2 moles of NH3
Explanation:
The balanced equation for the reaction is given below:
N2 + 3H2 —> 2NH3
From the balanced equation above,
1 mole of N2 reacted with 3 moles of H2 to produce 2 moles of NH3.
Thus, we can say that:
1 mole of N2 = 3 moles of H2
1 mole of N2 = 2 moles of NH3
3 moles of H2 = 2 moles of NH3
Thus, considering the options given above, the right answers to the question are:
2 moles NH3 = 1 mole of N2
3 moles of H2 = 1 mole of N2
3 moles of H2 = 2 moles of NH3
I am assuming that the compounds given are Pentane, 3-methyl-hexane, and 2, 4-dimethylpentane considering that the compounds were not separated by a comma.
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Pentane is in the form of a straight chain alkane. This is important as there are many isomers of Pentane, taking different shapes. By it's name it consists of 5 carbon atoms, and the number of hydrogen atoms should be 12, as the compound is nonpolar.
3-methylhexane is an alkane present in a hexane structure at position 3. There are thus 3 molecules at 3 ends of a hexane structure - H3C, CH3, and CH3
2,4-dimethylpentane is an alkane with respect to the formula [(H3C)2CH]2CH2.
With that information, refer to the three attachments below, for each compound given. They are in order -
Based on my knowledge and just completing Chemistry in 11th grade the I do believe the best answer here would be, C) "process of determining the amount of solute a solvent will hold." Hope this helped!
The balanced equation for the neutralisation reaction is as follows
2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O
stoichiometry of HNO₃ to Ba(OH)₂ is 2:1
number of Ba(OH)₂ mol present - 0.108 mol
1 mol of Ba(OH)₂ neutralises 2 mol of Ba(OH)₂
therefore 0.108 mol of Ba(OH)₂ neutralises - 2 x 0.108 mol = 0.216 mol of HNO₃
Answer:
Explanation
Let, Wavelength = W,
Given, frequency (f) = 50 Hz, wave velocity (V) = 342 m/s
We know, V = f × W
=> 342 = 50 × W
=> W = 342/50 metre
=> W = 6.84 metre
