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3 years ago

Draw the structures of the following compounds from their names: Pentane 3-methyl-hexane 2,4-dimethylpentane

Chemistry

1 answer:

Monica [59]3 years ago

8 0

I am assuming that the compounds given are Pentane, 3-methyl-hexane, and 2, 4-dimethylpentane considering that the compounds were not separated by a comma.

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Pentane is in the form of a straight chain alkane. This is important as there are many isomers of Pentane, taking different shapes. By it's name it consists of 5 carbon atoms, and the number of hydrogen atoms should be 12, as the compound is nonpolar.

3-methylhexane is an alkane present in a hexane structure at position 3. There are thus 3 molecules at 3 ends of a hexane structure - H3C, CH3, and CH3

2,4-dimethylpentane is an alkane with respect to the formula [(H3C)2CH]2CH2.

With that information, refer to the three attachments below, for each compound given. They are in order -

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One way in which elements differ from each other is the structure of the electron cloud in each element’s atoms. In an electron

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In the fermentation of glucose (wine making), 790 mL of CO2 gas was produced at 37 ∘C and 1.00 atm . You may want to reference (

Gennadij [26K]

<u>Answer:</u> The volume of the gas when the pressure and temperature has changed is 0.811 L

<u>Explanation:</u>

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

Conversion factor used:

1 L = 1000 mL

1 atm = 760 mmHg

$P_1=1.00atm=760mmHg\\V_1=790mL=0.790L\\T_1=37^oC=[37+273]K=310K\\P_2=695mmHg\\V_2=?L\\T_2=18^oC=[18+273]K=291K$

Putting values in above equation, we get:

$\frac{760mmHg\times 0.790L}{310K}=\frac{695mmHg\times V_2}{291K}\\\\V_2=\frac{760\times 0.790\times 291}{310\times 695}=0.811L$

Hence, the volume of the gas when the pressure and temperature has changed is 0.811 L

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3 years ago

The constant

Zigmanuir [339]

Answer:

75 kJ/mol

Explanation:

The reactions occur at a rate, which means that the concentration of the reagents decays at a time. The rate law is a function of the concentrations and of the rate constant (k) which depends on the temperature of the reaction.

The activation energy (Ea) is the minimum energy that the reagents must have so the reaction will happen. The rate constant is related to the activation energy by the Arrhenius equation:

ln(k) = ln(A) -Ea/RT

Where A is a constant of the reaction, which doesn't depend on the temperature, R is the gas constant (8.314 J/mol.K), and T is the temperature. So, for two different temperatures, if we make the difference between the two equations:

ln(k1) - ln(k2) = ln(A) - Ea/RT1 - ln(A) + Ea/RT2

ln (k1/k2) = (Ea/R)*(1/T2 - 1/T1)

k1 = 8.3x10⁸, T1 = 142.0°C = 415 K

k2 = 6.9x10⁶, T2 = 67.0°C = 340 K

ln(8.3x10⁸/6.9x10⁶) = (Ea/8.314)*(1/340 - 1/415)

4.8 = 6.39x10⁻⁵Ea

Ea = 75078 J/mol

Ea = 75 kJ/mol

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3 years ago

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Lana71 [14]

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