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Sunny_sXe [5.5K]
1 year ago
13

Consider the ions of potassium (K) and sulfur (S), Write chemical formulas for all possible ionic compounds involving these ions

, using the simplest ratio(s) of potassium (K) and sulfur (S). Keep in mind that the sum of the charges in an ionic compound must equal zero. Answer:​
Chemistry
2 answers:
Nookie1986 [14]1 year ago
6 0

The compounds between the ions K^+ and S^{2-} are K_2S.

<h3>What is an ionic compound?</h3>

An ionic compound is a compound that is composed of ions. Let us note that ionic compounds are always such that the sum of the charges on the ions is zero.

You need two potassium atoms to form an ionic bond with one sulfur atom. Potassium ions are formed by donating and losing their electrons in the outermost shell, the lost electrons are gained by sulphur atom to form 2K^+ and S^{2-}, respectively.

The attraction between the positive ions and negative ions gives rise to the ionic bond and the molecular formula is K_2S

Learn more about ionic compounds:

brainly.com/question/9167977

#SPJ1

attashe74 [19]1 year ago
4 0

The compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

<h3>What is an ionic compound?</h3>

An ionic compound is a commpound that is composed of ions. Let us note that ionic compounds are always such that the sum of the charges on the ions is zero.

Hence, the compounds that could exists between the ions K^+ and S^2- are K2S and K2S2.

Learn more about ionic compounds:brainly.com/question/9167977

#SPJ1

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Answer : The final temperature of the mixture is, 22.14^oC

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First we have to calculate the mass of ethanol and water.

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\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1.0g/mL\times 45.0mL=45.0g

Now we have to calculate the final temperature of the mixture.

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

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c_1 = specific heat of ethanol = 2.42J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of ethanol = 35.5 g

m_2 = mass of water = 45.0 g

T_f = final temperature of mixture = ?

T_1 = initial temperature of ethanol = 8.0^oC

T_2 = initial temperature of water = 28.6^oC

Now put all the given values in the above formula, we get:

35.5g\times 2.42J/g^oC\times (T_f-8.0)^oC=-45.0g\times 4.18J/g^oC\times (T_f-28.6)^oC

T_f=22.14^oC

Therefore, the final temperature of the mixture is, 22.14^oC

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