0.216g of aluminium compound X react with an excess of water water to produce gas. this gas burn completely in O2 to form H2O and 108cm^3of CO2 only . the volume of CO2 was measured at room temperature and pressure
0.108 / n = 24 / 1
n = 0.0045 mole ( CO2 >>0.0045 mole
0.216 - 0.0045 = 0.2115
so Al = 0.2115 / 27 => 0.0078 mole
C = 0.0045 * 1000 => 4.5 and Al = 0.0078 * 1000 = 7.8
Answer:
It's the last option.
Explanation:
H3PO4 + 5HCl → PCl5 + 4H2O
You subtract the atomic number from the atomic mass and you.
should get -125
Answer:
who knows lol but if you find out let me know
Hoffman Product is always a
less substituted alkene. In given scenario Structure
A (Given Below) was taken as a starting ch
iral Amine. For the sake of elimination the amine was taken tertiary so that on methylation it becomes a
good leaving group. This chiral amina (A) when treated with
Methyl Iodide gives a
quarternary amine which on treatment with Silver oxide yields less substituted Alkene (
B) as shown Below.
Alkene
B on Ozonolysis give two aldehydes i.e. Formaldehyde and Butyraldehyde.