The equation is (7^x)^4 = (7^2 × 7^3)/ 7^3x
(7^x)^4 is equal to 7^(4x)
7^2 × 7^3 is equal to 7^(2+3) which gives 7^5
therefore;
7^5/7^3x is equal to 7^(5-3x)
Hence we get;
7^(4x)=7^(5-3x)
thus; 4x = 5-3x
7x = 5 (solving for x)
Therefore; x = 5/7
Answer: C -7
Step-by-step explanation:
-2 x -7 = 14
14 - 10 = 4
hope this helps
Answer: (4,8)
First you have to solve for Y in either equation. I solved for Y in the second equation and my new equation was y=12-x.
Then you plug this new equation into the equation you did not touch. It will become 3x+ (12-x)=20.
Next you solve this equation for X which would be 4.
Lastly you plug in 4 in either equation. I plugged it in the first equation and it became 3(4)+y=20
I hope this helps some :)
Step-by-step explanation:
it is a multiple of 21.
the highest common factor of 2 numbers is the longest combination of prime factors they have in common.
the prime factors of 21 are simply
3×7
if another number A shares this as the longest combination of prime factors, that means it contains 3×7 itself in its prime factors.
and that means this number A can only be a multiple of 3×7 (= 21), as other prime factors present would be the factor of 21.
Im here but im not Crunch givin Buck
