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Neporo4naja [7]

3 years ago

5

Which expression has an equivalent value to x2 + 9x + 8 for all values of x?

2 answers:

Sindrei [870]3 years ago

7 0

The first one! hope it helps

guapka [62]3 years ago

5 0

First One

If you distribute this
(x*x) + (x*8) + (x*1) + (8*1)
x^2 + 8x + 1x + 8
x^2 + 9x + 8

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What is the slope of the line that passes through the points (9,6) and<br> (5, -8)?

LiRa [457]

Y2-y1
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-14
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= 14/4

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3 years ago

Which equation does the graph below represent

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Answer: The answer is y=-3x

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kirza4 [7]

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3 0

3 years ago

Read 2 more answers

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6 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago