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2 years ago

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Mathematics

1 answer:

vitfil [10]2 years ago

7 0

Answer:

Check the figure attached.

Step-by-step explanation:

We have

Expression in Rectangle 1= 4x+3y

Expression in Rectangle 2 = 2x-y

Their sum will be in circle 1

adding:

$4x+3y+2x-y \\=4x+2x+3y-y\\=6x+2y$

Now using the expression in Rectangle 3 and circle 3, we can find expression Of rectangle 4. Let it be Exp

$x+4y+Exp=4x+5y\\Exp=4x+5y-(x+4y)\\Exp=4x+5y-x-4y\\Exp=4x-x+5y-4y\\Exp=3x+y\\$

Now using Expression in rectangle 2 and 4 to find result for circle 3

$2x-y+3x+y\\=2x+3x-y+y\\=5x$

Now adding terms in the figure

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1. Rotate ABC 180° about the origin making<br> DEF.<br><br> List all congruent sides and angles:

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

To rotate point A 180° about the origin (point O) we draw a line from that point (A) throu the origin, measure the distance from the point A to the origin, and then measure the same distance on the other side of the origin to get rotated point. Mark it. The angle at the rotated point will be congruent to ∠A

The same goes for points B and C

Angles at pair of given and rotated point are congruent.

Sides of triangle are congruent if they lay between two congruent angles.

6 0

3 years ago

Rt=R1 R2__, determined Rt when R1=100 and R2 =200?<br>R1+R2 (electronics)

zloy xaker [14]

Answer:

$R_t=300\ \Omega$

Step-by-step explanation:

Given that,

R₁ = 100 ohms

R₂ = 200 ohms

We need to find the equivalent resistance of the circuit. So,

$R_t=R_1+R_2\\\\R_t=100+200\\\\R_t=300\ \Omega$

So, the equivalent resistance is $300\ \Omega$ .

7 0

3 years ago

Determining Exponential Growth and Decay in Exercise, use the given information to write an exponential equation for y. Does the

scZoUnD [109]

Answer:

$y=20e^{-\frac{2}{3}t}$

Exponential decay

Step-by-step explanation:

We are given that

$\frac{dy}{dt}=-\frac{2}{3}y$

y=20 when t=0

$\frac{dy}{y}=-\frac{2}{3}dt$

Taking integration on both sides then we get

$lny=-\frac{2}{3}t+C$

Using formula $\int \frac{dx}{x}=lnx,\int dx=x$

$y=e^{-\frac{2}{3}t+C}$

Using formula

$lnx=y\implies x=e^y$

$y=e^C\cdot e^{-\frac{2}{3}t}$

$e^C=Constant=C$

$y=Ce^{-\frac{2}{3}t}$

Substitute y=20 and t=0

$20=C$

Substitute the value of C

$y=20e^{-\frac{2}{3}t}$

When t tends to infinity then

$\lim_{t\rightarrow\infty}=\lim_{t\rightarrow\infty}20e^{-\frac{2}{3}t}=0$

When time increases then the value of function decrease

Hence, the function is exponential decay.

8 0

3 years ago

What is the average speed of a car that travels 440 km in 15.4 hours?

n200080 [17]

A car travels 440km in 15.4 hours -> In 1 hour, the car travel 1/(15.4) the distance.

So in an hour, the car travel : 440 x 1/(15.4) = 28.5714285714... (round to 29)

So, the average speed of the car is approximately 29 km/h

4 0

2 years ago

For males in a certain town, the systolic blood pressure is normally distributed with a

telo118 [61]

Answer: (92, 128)

Step-by-step explanation:

According to the Empirical rule,

If the population is normallly distributed, then 95% of the population lies within 2 standard deviations from the mean.

Given: Mean = 110

Standard deviation = 9

The interval of systolic blood pressures represent the middle 95% of males:

(110-2(9), 110+2(9))

= (110-18, 110+18)

= (92, 128)

Hence, the interval of systolic blood pressures that represent the middle 95 % of males = (92, 128)

4 0

3 years ago