How many times do you need to divide by ten to get from 940.0 to 9.400
2 answers:
<h3><u>Answer: </u><u>2 times</u></h3>
Step-by-step explanation: Dividing decimals is the same concept as moving the decimal to the left. In this case, all you need to do is count how many digits to the left the decimal moved from 940.0 to 9.400:
(View image below)
As you can see, we had to move the decimal 2 places to the left to get to 9.400. So, you need to divide by ten 2 times to get from 940.0 to 9.400.
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Answer:
The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.
Step-by-step explanation:
From the question, we have the following information:
- The distribution for protein requirement is <em>normally distributed</em>.
- The population mean for protein requirement for adults is
- The population standard deviation is
We have here that protein requirements in adults is normally distributed with defined parameters. The question is about <em>the proportion</em> <em>of the population</em> that has a requirement less than .
For answering this, we need to calculate a <em>z-score</em> to obtain the probability of the value <em>x </em>in this distribution using a <em>standard normal table</em> available on the Internet or on any statistics book.
<h3>z-score</h3>A z-score is expressed as
For the given parameters, we have:
With this value for <em>z</em> at hand, we need to consult a standard normal table to determine what the probability of this value is.
The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is <em>symmetrical</em>.
Tables have values for <em>z</em> with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the <em>standard normal table</em> gives a value of P(z<0.71) = 0.76115.
Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:
(rounding to three decimal places)
That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is
See the graph below. The shaded area is the region that represents the proportion asked in the question.
