More card math! Easy!!
Exactly 1/4 of a 52-card deck of cards is clubs. Another 1/4 spades, another 1/4 is hearts, and the final 1/4 is diamonds. To find what one fourth of 52is, you can divide 52 by 4. That equals 13. So there are 13 clubs in the entire deck of cards. If you are trying <em>not </em>to get a club, you have to find the remainder of the cards without those 13. 52 - 13 = 39. This means that you have 39/52 odds of <em>not </em>getting a club. Simplified you get 3/4.
I did it the long way. A shorter was is to see that, obviously, one whole minus one fourth is three fourths.
Ok so, we have the fact that 1.20 per mile Lets represent m as each additional mile so we have 1.20m which is That much per additional mile So For the first 5 functions we have f(1) = 20 f(2) = 20 f(3) = 20 f(4) = 20 f(5) = 20 Only for the first 5 miles though, since it is a flat fee. So for the additional miles we go back to what I said in the first Paragraph. 1.20m That is for additional miles, so that will be added to 20 So if you travel more than 5 miles the function looks like this: f(x) = 20 + 1.20m So the first 5 miles it is: f(x) = 20 For 7 mles the function would look like: f(7) = 20 + 1.20(2) It is a 2 because it is the additional mile, which is 2 hope this helps
The correct answer would be D, because there’s no other leading common factors between the two besides one.
The unites to measure the volume of an object is what ever units you’re using cubed
Answer:
D) 0 = 2(x + 5)(x + 3)
Step-by-step explanation:
Which of the following quadratic equations has no solution?
We have to solve the Quadratic equation for all the options in other to get a positive value as a solution for x.
A) 0 = −2(x − 5)2 + 3
0 = -2(x - 5) × 5
0 = (-2x + 10) × 5
0 = -10x + 50
10x = 50
x = 50/10
x = 5
Option A has a solution of 5
B) 0 = −2(x − 5)(x + 3)
Take each of the factors and equate them to zero
-2 = 0
= 0
x - 5 = 0
x = 5
x + 3 = 0
x = -3
Option B has a solution by one of its factors as a positive value of 5
C) 0 = 2(x − 5)2 + 3
0 = 2(x - 5) × 5
0 = (2x -10) × 5
0 = 10x -50
-10x = -50
x = -50/-10
x = 5
Option C has a solution of 5
D) 0 = 2(x + 5)(x + 3)
Take each of the factors and equate to zero
0 = 2
= 0
x + 5 = 0
x = -5
x + 3 = 0
x = -3
For option D, all the values of x are 0, or negative values of -5 and -3.
Therefore the Quadratic Equation for option D has no solution.
