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Pavel [41]
3 years ago
13

In this problem, we explore the effect on the mean, median, and mode of adding the same number to each data value. Consider the

data set 6, 6, 7, 10, 14.
Mathematics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer

The mean is 8.6

The median is 7

And the mode is 6

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First choose which of the following statements are correct. If there is more than one reason why the system is not in echelon fo
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D. The system is in echelon form.

Step-by-step explanation:

Check attachment

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200 feet in 5 minutes
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Q#2 Graph the relation in the table.Then use the vertical-line test.Is the relation a function
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The graph of the relation between x and y is as shown in attached figure

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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This means that p = 0.95

10 targets

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Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

P(X = 10) + P(X < 10) = 1

We want P(X < 10). So

P(X < 10) = 1 - P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987

P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401

40.1% probability that he will miss at least one of them

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Answer:

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