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guapka [62]
3 years ago
8

a store had 44 regular sodas, both diet and regular. the ratio of diet sodas to regular sodas was 8:4. how many diet sodas were

there?
Mathematics
1 answer:
timurjin [86]3 years ago
7 0
There are 88 diet sodas
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What is the doubling time?
marusya05 [52]
<span>The doubling time is the period of time required for a quantity to double in size or value. It is applied to population growth, inflation, resource extraction, consumption of goods, compound interest, the volume of malignant tumours, and many other things that tend to grow over time.</span>
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2 Name the diameter of the circle shown. <br>A co <br>B ec<br>C eo<br>D rc​
Orlov [11]

Answer: a

Step-by-step explanation:

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3 years ago
How much simple interest would 1000 earn in 275 days at an interest rate of 4.21%
nikitadnepr [17]
Now, there are 365 (excluding leap years) in a year, so, 275 days is not even a year, but is  275/365 of a year, or 55/73 of a year.

\bf \qquad \textit{Simple Interest Earned}\\\\&#10;I = Prt\qquad &#10;\begin{cases}&#10;I=\textit{interest earned}\\&#10;P=\textit{original amount deposited}\to& \$1000\\&#10;r=rate\to 4.21\%\to \frac{4.21}{100}\to &0.0421\\&#10;t=years\to \frac{275}{365}\to &\frac{55}{73}&#10;\end{cases}&#10;\\\\\\&#10;I=1000\cdot 0.0421\cdot \cfrac{55}{73}
3 0
3 years ago
A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari
guajiro [1.7K]

Answer:

a

The null hypothesis is  H_o :  \sigma^2_1 = \sigma^2 _2

The alternative hypothesis is H_a :  \sigma_1 ^2 > \sigma^2_2

b

F_{critical} = 1.8608

c

F = 2.9085

d

    The decision rule is  

Reject the null hypothesis

e

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

 The first sample size is  n_1 = 30

 The sample variance for elementary school is  s^2_1 = 8324

 The second sample size is  n_2 = 30

  The sample variance for the secondary school is  s^2_2 = 2862

   The significance level is  \alpha = 0.05

The null hypothesis is  H_o :  \sigma^2_1 = \sigma^2 _2

The alternative hypothesis is H_a :  \sigma_1 ^2 > \sigma^2_2

Generally from the F statistics table  the critical value of \alpha = 0.05 at first and  second degree of freedom df_1 = n_1 - 1 = 30 - 1 = 29 and  df_2 = n_2 - 1 = 30 - 1 = 29 is  

         F_{critical} = 1.8608

Generally the test statistics is mathematically represented as

       F = \frac{s_1^2 }{s_2^2}

=>   F = \frac{8324 }{2862}

=>   F = 2.9085

Generally from the value obtained we see that  F >  F_{critical } Hence

   The decision rule is  

Reject the null hypothesis

    The conclusion is  

  There is sufficient evidence to support the researchers claim

   

4 0
3 years ago
A sealed-tube manometer can be used to measure pressures below atmospheric pressure. The tube above the mercury is evacuated. Wh
sp2606 [1]
The <u>correct answers</u> are:

6.5 cm = 65.00001052 torr
6.5 cm = 8665.93 Pa
6.5 cm = 0.08552632119 atm

Explanation

The conversion rate from centimeters mercury (cm Hg) to torr is
1 torr = 0.099999983814461 cm.

We have 6.5 cm; this means to convert we divide:
6.5/0.099999983814461 = 65.00001052

The conversion rate from cm Hg to Pascals (Pa) is
1 cm = 1333.22 Pa

We have 6.5 cm; this means to convert we multiply:
6.5(1333.22) = 8665.93

The conversion rate from cm Hg to atmospheres (atm) is
1 atm = 75.999995199606 cm

We have 6.5 cm; this means to convert we divide:
6.5/75.999995199606 = 0.08552632119
7 0
3 years ago
Read 2 more answers
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