-6/10×-1/8=3/40? is this correct

30 points: Answer the questions in the picture provided

Pie

1). Enrico Fermi directed construction of the the thing
that achieved the first sustained nuclear chain reaction,
under the stadium at the University of Chicago.

3). 'Fission' means splitting one big thing up into several
smaller things.

4). The atomic mass of an atom is close to the sum of all
the neutrons and protons in its nucleus.

5). 'Fusion' means several small things joining to form a
bigger thing.

6). Henri Becquerel is credited with discovering radioactivity.

7). The names of Madame Marie and Mssr. Pierre Curie were
appropriated after their deaths and used as the unit of radiation.

2). I have no idea what that symbol means, but 'neutron' is
the only choice left.

5 0

2 years ago

Expand 4(z+6) into the simplest form.

Ratling [72]

4z + 24 is the answer

4 0

2 years ago

A loaf of bread that is baked today costs $7. All of the bread baked yesterday is 40% off.

vovikov84 [41]

Answer:

The price of today's bread is $7.

40% of $7 is $2.80.

The price of yesterdays bread is $7-$2.80.

7-2.80=4.20

The price of yesterday's bread is $4.20

Tobin has enough money to purchase a loaf of yesterday's bread.

Hope this helps!

4 0

3 years ago

7) PG & E have 12 linemen working Tuesdays in Placer County. They work in groups of 8. How many

BabaBlast [244]

Part A

Since order matters, we use the nPr permutation formula

We use n = 12 and r = 8

$_{n}P_{r} = \frac{n!}{(n-r)!}\\\\_{12}P_{8} = \frac{12!}{(12-8)!}\\\\_{12}P_{8} = \frac{12!}{4!}\\\\_{12}P_{8} = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\\\_{12}P_{8} = \frac{479,001,600}{24}\\\\_{12}P_{8} = 19,958,400\\\\$

There are a little under 20 million different permutations.

<h3>Answer: 19,958,400</h3>

Side note: your teacher may not want you to type in the commas

============================================================

Part B

In this case, order doesn't matter. We could use the nCr combination formula like so.

$_{n}C_{r} = \frac{n!}{r!(n-r)!}\\\\_{12}C_{8} = \frac{12!}{8!(12-8)!}\\\\_{12}C_{8} = \frac{12!}{4!}\\\\_{12}C_{8} = \frac{12*11*10*9*8!}{8!*4!}\\\\_{12}C_{8} = \frac{12*11*10*9}{4!} \ \text{ ... pair of 8! terms cancel}\\\\_{12}C_{8} = \frac{12*11*10*9}{4*3*2*1}\\\\_{12}C_{8} = \frac{11880}{24}\\\\_{12}C_{8} = 495\\\\$

We have a much smaller number compared to last time because order isn't important. Consider a group of 3 people {A,B,C} and this group is identical to {C,B,A}. This idea applies to groups of any number.

-----------------

Another way we can compute the answer is to use the result from part A.

Recall that:

nCr = (nPr)/(r!)

If we know the permutation value, we simply divide by r! to get the combination value. In this case, we divide by r! = 8! = 8*7*6*5*4*3*2*1 = 40,320

So,

$_{n}C_{r} = \frac{_{n}P_{r}}{r!}\\\\_{12}C_{8} = \frac{_{12}P_{8}}{8!}\\\\_{12}C_{8} = \frac{19,958,400}{40,320}\\\\_{12}C_{8} = 495\\\\$

Not only is this shortcut fairly handy, but it's also interesting to see how the concepts of combinations and permutations connect to one another.

-----------------

<h3>Answer: 495</h3>

5 0

2 years ago

Please help I'm really confused I need have with these 6 questions

Lelechka [254]

Ahh, basic shapes. Split up the weird shapes into easier ones. #1 can be truned into 2 trapezoids. #2 can be turned into 2 circles. #3 is a triangle and a trapezoid. #4 is 2 right triangles. #5 is a rectangel and a traingle. Finally, #6 is 3 traigles and a rectangle. Do you see how we broke the hard shapes into easier shapes?

6 0

2 years ago