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Ilya [14]
3 years ago
5

Please help me with this question

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0

Answer:

cos(x-30)=1/2

Step-by-step explanation:

We use the following relationship to obtain cos(x)

sin^{2}(x) +cos^{2}(x) +1

From that, we have that cos(x)= sqrt(1-1/4)=sqrt(3) / 4

To obtain the value of cos(x-30), lets remember the following expression:

cos(a-b)=cos(a)*cos(b)+sin(a)*sin(b)

Therefor, we can use that to obtain our desired function cos(x-30)

cos(x)*cos(30)+sin(x)*sin(30)

\frac{\sqrt{3} }{2} * \frac{\sqrt{3} }{2}  +\frac{-1}{2}*\frac{1}{2}

=2/4=1/2

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Simplify: 2(x+6) show work please
vagabundo [1.1K]

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I’m pretty sure a is always and b is sometimes.
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2 years ago
6x + 5y = 147<br> 8x + 4y = 156
satela [25.4K]

Answer:

[12, 15]

Step-by-step explanation:

{6x + 5y = 147

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-¾[8x + 4y = 156]

{6x + 5y = 147

{-6x - 3y = -117 ← New Equation

________________

2y = 30

___ ___

2 2

y = 15 [Plug this back into both equations to get the x-coordinate of 12]; 12 = x

So, using the Elimination Method, what I did here was took the bottom equation and multiplied it by -¾, turning 8x to -6x, canceling out all <em>x-terms</em><em>.</em><em> </em>It does not matter which variable you choose to eliminate, as long as you know what you are doing.

I am joyous to assist you anytime.

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