Which of the following is a conjugate for 7 + iSquare root of 2? a. − 7 + iSquare root of 2

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The complex conjugate of a complex number is the number with equal real part and imaginary part equal in magnitude but opposite sign.
z = 7 + i√2
Answer: the conjugate is B ) 7 - i √2

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cestrela7 [59]

Answer:

Step-by-step explanation:

Work is shown in the picture below. I split the work of solving the numerator and denominator apart so it's easier to understand.

The most confusing part may be solving the $\frac{2}{\frac{1}{3} }$ . However, it's basically asking you to divide 2 by $\frac{1}{3}$ . Remember that in order to divide something in fraction form, you the "flip" the numerator and denominator of the divisor, meaning the numerator now becomes the denominator and the denominator now becomes the numerator. This results in $\frac{2}{1}$ · $\frac{3}{1}$ part - notice how the $\frac{1}{3}$ was flipped to $\frac{3}{1}$ .