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Oduvanchick [21]
4 years ago
7

A proton is moving toward a stationary charged particle. Which statement correctly describes an energy change that could occur a

s the particles get closer?
A. Kinetic energy will be converted into electric potential energy if the stationary particle is positive.
B. Kinetic energy will be converted into electric potential energy if the stationary particle is negative.
C. Electric potential energy will be converted into kinetic energy if the stationary particle is positive.
D. Electric potential energy will be converted into thermal energy if the stationary particle is negative.
Physics
2 answers:
nikdorinn [45]4 years ago
5 0
<span>A. Kinetic energy will be converted into electric potential energy if the stationary particle is positive.</span>
Vadim26 [7]4 years ago
4 0

Answer: The correct option is A.

Explanation:

The electric potential energy is defined as the work done required in assembling the charges by bringing them close together.

The kinetic energy is due to the motion of the particle.

In the given problem, a proton is moving towards a stationary charged particle. There will an energy change that could occur as the particles get closer.

The moving charge gains electric potential energy and losses its kinetic energy until it stops.

At that point, Kinetic energy will be converted into electric potential energy if the stationary particle is positive.

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An object is transported to three different planets in our solar system. Which of the following is true about that object?
Digiron [165]

<u>Answer;</u>

<em>D.  The object’s weight changes, but its mass stays the same.</em>

<u>Explanation;</u>

  • Mass is the amount of matter in a object, which is measured in kilograms. Mass of an object is measured using a beam balance. It is important to note that the mass of an object or a body remains constant, and does not vary from one place to another. For instance the mass of a person on the moon will be the same as when the person is on the earth surface.
  • Weight on the other hand is the measurement of gravitational pull of an object. weight is measured using a spring balance and measured in Newtons. Weight varies from one place to another depending on the gravitational pull of a given surface.
8 0
3 years ago
Read 2 more answers
1. A Zambeef delivery track travels 18 km north, 10 km east, and 16 km south. What is its final displacement from the origin?
VARVARA [1.3K]

Answer:

2km

Explanation:

Given data

We are told that the direction traveled are

North>>>East>>>South

Hence the displacement is defined as the distance away from the initial position is

Initial position =18km

FInal position = 16km

The displacement = 18-16= 2km

Hence the displacement is 2km

6 0
3 years ago
A satellite dish is shaped like a paraboloid of revolution. This means that it can be formed by rotating a parabola around its a
pentagon [3]

Answer:

Explanation:

Given dish width= 48ft

Depth = 4ft

Using equation of a parabola

x²= 4py

48² = 4p 4

4p = 576

P= 144ft

Thus the the receiver should be placed 144ft from t the vertex

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3 years ago
Example of first, second and third law of motion.​
statuscvo [17]

Examples of Newton's three law of motion.

First law of motion: A rocket being launched up in the atmosphere.

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Hope,it will helpyouu!

4 0
3 years ago
A uniform beam with mass M and length L is attached to the wall by a hinge, and supported by a cable. A mass of value 3M is susp
Jobisdone [24]

Answer:

The tension is  T= \frac{11}{2\sqrt{3} } Mg

The horizontal force provided by hinge   Fx= \frac{11}{4\sqrt{3} } Mg

Explanation:

   From the question we are told that

          The mass of the beam  is   m_b =M

          The length of the beam is  l = L

           The hanging mass is  m_h = 3M

            The length of the hannging mass is l_h = \frac{3}{4} l

            The angle the cable makes with the wall is \theta = 60^o

The free body diagram of this setup is shown on the first uploaded image

The force F_x \ \ and \ \ F_y are the forces experienced by the beam due to the hinges

      Looking at the diagram we ca see that the moment of the force about the fixed end of the beam along both the x-axis and the y- axis is zero

     So

           \sum F =0

Now about the x-axis the moment is

              F_x -T cos \theta  = 0

     =>     F_x = Tcos \theta

Substituting values

            F_x =T cos (60)

                 F_x= \frac{T}{2} ---(1)

Now about the y-axis the moment is  

           F_y  + Tsin \theta  = M *g + 3M *g ----(2)

Now the torque on the system is zero because their is no rotation  

   So  the torque above point 0 is

          M* g * \frac{L}{2}  + 3M * g \frac{3L}{2} - T sin(60) * L = 0

            \frac{Mg}{2} + \frac{9 Mg}{4} -  T * \frac{\sqrt{3} }{2}    = 0

               \frac{2Mg + 9Mg}{4} = T * \frac{\sqrt{3} }{2}

               T = \frac{11Mg}{4} * \frac{2}{\sqrt{3} }

                   T= \frac{11}{2\sqrt{3} } Mg

The horizontal force provided by the hinge is

             F_x= \frac{T}{2} ---(1)

Now substituting for T

              F_{x} = \frac{11}{2\sqrt{3} } * \frac{1}{2}

                  Fx= \frac{11}{4\sqrt{3} } Mg

4 0
3 years ago
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