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3 years ago

A) If the mass of the car is doubled (by adding passengers and cargo) by what factor must the

Physics

1 answer:

Nostrana [21]3 years ago

5 0

Let Mass be m

F=ma

If its doubled then

$\\ \sf\longmapsto F=2ma$

Hence force also needs to be doubled.

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The water that powers the generators enters and leaves the system at a low speed (thus we can neglect its change of kinetic ener

madam [21]

Answer:

Explanation:

Let density of water be ρ .

During flow , volume of water flowing per second is constant

loss of P. E per unit volume = ρ gh , 83.5 % is lost

Gain of K E per unit volume = 1/2 ρ v²

83.5 % of mgh = ρ 1/2 ρ v²

1/2 ρ v² = .835 x 9.8

v² = 2 x .835 x 9.8

= 16.366

v = 4.04 m /s

4 0

4 years ago

Pls help it's due today

mario62 [17]

Answer:

Breh seriously. Ugh fine.

1.B

2.D

3.C

4.C

5.D,A and B

6.A,C and D

3 0

2 years ago

A 20.0-µF capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280

natali 33 [55]

Answer

given,

Capacitance of capacitor = 20.0-µF

Voltage = 150.0-V

inductance = 0.280 m H

a) the oscillation frequency of circuit

$f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{LC}}$

$f = \dfrac{1}{2\pi}\ sqrt{\dfrac{1}{0.280 \times 10^{-3}\times 20 \times 10^{-6}}}$

f = 2126.9 Hz

b) $U = \dfrac{1}{2}CV^2$

$U = \dfrac{1}{2}(20\times 10^{-6})(150)^2$

U = 0.225 J

c)Current in the inductor

$V = L \dfrac{dI}{dt}$

$150 = 0.28 \times 10^{-3} \dfrac{dI}{dt}$

$\dfrac{dI}{dt} = 535714$

instantaneous rate of change of current is equal to 535714 A/s

7 0

3 years ago

Suppose a treadmill has an average acceleration of 4.7x10^-3 m/s. a)how much does its speed change after 5min? b)if the treadmil

Mars2501 [29]

Answer:

a)Change in the speed = 1.41 m/s

b)The final speed will be 3.11 m/s

Explanation:

Given that

Acceleration ,a= 4.7 x 10⁻³ m/s²

We know that

v= u + a t

v=final speed ,u=initial speed

t= time ,a= acceleration

Change in the speed

v- u = a t

t= 5 min = 5 x 60 s = 300 s

v- u = 4.7 x 10⁻³ x 5 x 60 m/s

v-u = 1.41 m/s

Change in the speed = 1.41 m/s

Given that

u= 1.7 m/s

v-u = 1.41 m/s

v= 1.7 + 1.41 m/s

v=3.11 m/s

The final speed will be 3.11 m/s

8 0

3 years ago

A loop of wire is perpendicular to a magnetic field such that the field is coming straight at you through the loop. The field be

Umnica [9.8K]

Answer:

we will have induced magnetic field towards us

now in order to induce the magnetic field towards us we must have induced current in the loop and its direction is counterclockwise.

Explanation:

As per lenz law we know that the rate of change in magnetic flux linked with the closed loop will induced EMF in the loop and the direction of this induced current in the loop will always oppose the causes due to which it is induced

Here we know that magnetic field is straight towards us and it start decreasing with time

So we can say that flux linked with the coil will also decrease with time

Now as per lenz law the induced magnetic field of the loop is in such a direction that it will increase the magnetic flux in the coil.

So we will have induced magnetic field towards us

now in order to induce the magnetic field towards us we must have induced current in the loop and its direction is counterclockwise.

5 0

3 years ago