Answer:
a. C(x) = 24,000 + 100x
b. R(x) = 200x
c. Break-even point is 240 canoes
Step-by-step explanation:
a. Cost function is C(x) = FC + pcost * x
C(x) = 24,000 + 100x
Where
FC=Fixed cost = 24,000
pcost=costs to prod canoes = $100
x=produce quantity
b.Revenue function
R(x) = Px * x
R(x) = 200x
Where
Px=Price
x=produce quantity
c. Break-even point is the amount of canoes where revenue are the same as cost. We cover the total cost with the sales.
So, FC + pcost * x=Px * x
24,000 + 100x=200x
Isolating x
24,000 =200x- 100x
100x=24000
x=24,000/100
x=240
Answer:
f(-3)=-8
Step-by-step explanation:
plug -3 in as x
-4(-3+5)
12-20
-8
Answer:
$9.60
Step-by-step explanation:
The question above is a simple interest question.
The formula for the amount of money after a given period of time using simple interest is given as:
A = P(1 + rt)
Where
P = Initial Amount saved or invested = $8
R = Interest rate = 5%
t = Time in years = 4
Calculation:
First, converting R percent to r a decimal
r = R/100 = 5%/100 = 0.05 per year.
Solving our equation:
A = 8(1 + (0.05 × 4)) = 9.6
A = $9.60
The amount of money that will be in a bank account after 4 years is $9.60
Answer:
x = - , x =
Step-by-step explanation:
Given
x² - x - = 0
Multiply through by 4 to clear the fraction
4x² - 4x - 3 = 0
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 4 × - 3 = - 12 and sum = - 4
The factors are + 2 and - 6
Use these factors to split the x- term
4x² + 2x - 6x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(2x + 1) - 3(2x + 1) = 0 ← factor out (2x + 1) from each term
(2x + 1)(2x - 3) = 0
Equate each factor to zero and solve for x
2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = -
2x - 3 = 0 ⇒ 2x = 3 ⇒ x =
Answer/Step-by-step explanation:
✔️Find EC using Cosine Rule:
EC² = DC² + DE² - 2*DC*DE*cos(D)
EC² = 27² + 14² - 2*27*14*cos(32)
EC² = 925 - 756*cos(32)
EC² = 283.875639
EC = √283.875639
EC = 16.85 cm
✔️Find the area of ∆DCE:
Area = ½*14*27*sin(32)
Area of ∆DCE = 100.15 cm²
✔️Since ∆DCE and ∆ABE are congruent, therefore,
Area of ∆ABE = 100.15 cm²
✔️Find the area of the sector:
Area of sector = 105/360*π*16.85²
Area = 260.16 cm² (nearest tenth)
✔️Therefore,
Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)