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djyliett [7]
3 years ago
9

Find the absolute mean deviation for the set {X, 2x, 3x, 4x}

Mathematics
1 answer:
OlgaM077 [116]3 years ago
8 0

Given:

Data set = \{x, 2x, 3x, 4x\}

To find:

The absolute mean deviation for the given set.

Solution:

We have,

Data set = \{x, 2x, 3x, 4x\}

Mean of the data set is

Mean=\dfrac{\sum x_i}{n}

Mean=\dfrac{x+2x+3x+4x}{4}

Mean=\dfrac{10x}{4}

Mean=2.5x

Now,

The formula for mean absolute deviation (MAD) is

MAD=\dfrac{\sum |x_i-\overline x|}{n}

MAD=\dfrac{|x-2.5x|+|2x-2.5x|+|3x-2.5x|+|4x-2.5x|}{4}

MAD=\dfrac{|-1.5x|+|-0.5x|+|0.5x|+|1.5x|}{4}

MAD=\dfrac{1.5x+0.5x+0.5x+1.5x}{4}

MAD=\dfrac{4x}{4}

MAD=x

Therefore, the mean absolute deviation for the given set of data is x.

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C

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Trapezoid WKLX has vertices W(2, −3), K(4, −3), L(5, −2) , and X(1, −2) . Trapezoid WKLX ​ is translated 4 units right and 3 uni
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dem82 [27]

Answer:

15 times 2 - 26 = x

Step-by-step explanation:

Warren drives half the distance Kendall drives to work. Kendall drives 26 more miles to work than Joe. Warren drives 15 miles. Write an equation that models this situation. Use x to represent the number of miles Joe drives to work.

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Ber [7]

Answer:

<h2>m∠ACE = 90°</h2>

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Figure Interpretation:

m∠CBA + m∠CDE = 180

m∠BCA = (180-m∠CBA)/2

m∠DCE = (180-m∠CDE)/2

=======================

Then

m∠BCA + m∠DCE = (180-m∠CBA)/2 + (180-m∠CDE)/2

                                = [360-(m∠CBA+m∠CDE)]/2

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finally,

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