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DaniilM [7]
2 years ago
7

Help please i will mark brainliest if the answer is correct

Mathematics
1 answer:
inysia [295]2 years ago
7 0

Answer:

2

-2

-1.5/7,-1)

-2

2

Step-by-step explanation:

Also your first answer is correct ma'am or sir! thank me later

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Line AB passes through points A (-6,6) and B(12,3). If the equation of the line is written in slope-intercept form, y=mx+b, the.
Tomtit [17]

Answer:

You wrote the question wrong...

m is not -16 it is -1/6 (that is a big difference)

y=mx+b

y=-1/6x+b

3 = -1/6(12) + b

3 = -2 + b

b=5

Step-by-step explanation:

3 0
2 years ago
Need alot of help please!!!
kirza4 [7]
A=x
B= 2x
C=3x
If you add them up =
6x =180
÷6 both sides
x=30
A=30
B=60
C=90
one angle is 90 degrees so the triangle is classified as a right triangle
8 0
3 years ago
Read 2 more answers
Solve the formula D=a+b−c for b in general.
kari74 [83]

Answer:

b = c - a - D

Step-by-step explanation:

D=a+b−c \\ b = c  - a - D

3 0
3 years ago
ON YOUR OWN
vichka [17]
5 units because your starting from (-2,-2) so the last -2 will stay and the first number(-2) will go up until you hit the (,3) which will be 5 units away
6 0
2 years ago
Read 2 more answers
What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?
Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

AB = \sqrt{(11-4)^{2}+(3-3)^{2}}

AB = \sqrt{(7)^{2}+(0)^{2}}

AB = \sqrt{49}

\sqrt{49} =7

AB = 7 units

As take B(11, 3) to C (11, 9).

BC = \sqrt{(11-11)^{2}+(9-3)^{2}}

BC = \sqrt{(0)^{2}+(6)^{2}}

BC = \sqrt{36}

\sqrt{36} =6

BC = 6 units

As take C (11, 9) toD (4, 9).

CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}

CD = \sqrt{(7)^{2}+(0)^{2}}

CD = \sqrt{49}

\sqrt{49} =7

CD =  7 units

As take  D (4, 9) to  A (4, 3)

DA = \sqrt{(4-4)^{2}+(3-9)^{2}}

DA = \sqrt{(0)^{2}+(-6)^{2}}

DA = \sqrt{36}

\sqrt{36} =6

DA =  6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value  in the above

Area of rectangle =  7 × 6  

                             = 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0
3 years ago
Read 2 more answers
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