Answer:
89
Step-by-step explanation:
Given that,
During a promotional weekend, a state fair gives a free admission to every 179th person that enters the fair.
No of people attending the fair on Saturday is 8,633 amd No of people attending the fair on Sunday is 7,400.
We need to find the no of people that received a free admission over the two days.
Dividing 8,633 by 179 gives 48 as quotient and 41 as remainder. It means on Saturday 48 people entered for free.
Dividing 7,400 by 179 gives 41 as quotient and 61 as remainder. It means on Sunday 41 people entered for free.
Total no of people,
T = 48 + 41
T = 89
Hence, there are 89 people for free entries.
I would love to help, but what are the options?
7 = 2n - 2
n= a number so twice a number is 2n and 7 is 2 less than twice this number.
7]
6/(x-1)-5x/4
subtracting the above we put the fraction under the same denominator:
6/(x-1)-5x/4
multiplying the denominators we get:
4(x-1)
thus subtracting we get:
6/(x-1)-5x/4
=(4*6-5x(x-1))/[4(x-1)]
=[24-5x^2+5x]/(4x-4)
Answer:
(-5x^2+5x+24)/(4x-4)
9]
3/(x+7)+4/(x-8)
the common denominator is:
(x+7)*(x-8)=(x+7)(x-8)
thus adding the fractions we put them under the same denominator as follows:
[3(x-8)+4(x+7)]/[(x+7)(x-8)]
=[3x-24+4x+28]/[(x+7)(x-8)]
=(7x+4)/[(x+7)(x-8)]
