20% de 75 es 50...<span>Es el iniciador</span>
        
                    
             
        
        
        
The pH of the weak acid is 3.21
Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :
![[H^{+}]=\sqrt{Ka . Ma}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%3D%5Csqrt%7BKa%20.%20Ma%7D)
where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.
Since we know the concentration of H+, the pH can be calculated by using
pH = -log[H+]
From question above, we know that :
Ma = 0.0250M
Ka = 1.5 x 10¯⁵
By using the equation, we can determine the concentration of [H+]
[H+] = √(Ka . Ma)
[H+] = √(1.5 x 10¯⁵ . 0.0250)
[H+] = 6.12 x 10¯⁴ M
Substituting the value of [H+] to get the pH
pH = -log[H+]
pH = -log(6.12 x 10¯⁴)
pH = 3.21
Hence, the pH of the weak acid c3h7cooh is 3.21
Find more on pH at: brainly.com/question/14466719
#SPJ4
 
        
             
        
        
        
New annual renter's insurance premium = 325(1 + 0.18) = 325 x 1.18 = $383.50
        
                    
             
        
        
        
The function is:
f ( x ) = 2 / ( x² + 3 x - 10 )
x² + 3 x - 10 = x² + 5 x - 2 x - 10 = x ( x + 5 ) - 2 ( x + 5 ) = 
= ( x + 5 ) ( x - 2 )
x + 5 = 0 => x = - 5
x - 2 = 0 => x = 2
Answer:
The vertical asymptotes are: x = - 5 and x = 2.
        
             
        
        
        
(-2.3)*4.7 would be equal to -10.81