No
It is not proportional, because when x = 0, y does not equal 0.
when x = 0, y = -4. Therefore, it doesnt pass through the origin.
Answer:
<em>He should use 800 pounds of trail mix 5% raisins and 200 pounds of trail mix 20% raisins</em>
Step-by-step explanation:
<u>System of Equations</u>
Let's call
x = pounds of trail mix 5% raisins
y = pounds of trail mix 20% raisins
The distributor wants to make 1,000 pounds of trail mix, thus:
x + y = 1,000 [1]
The mix must be 8% raisings as a combination of x and y, thus:
5x + 20y = 8*1,000 = 8,000
Dividing by 5:
x + 4y = 1,600 [2]
Subtracting [2] and [1]:
4y - y = 1,600 - 1,000
Operating:
3y = 600
y = 200
From [1]
x = 1,000 - y = 1,000 - 200
x = 800
He should use 800 pounds of trail mix 5% raisins and 200 pounds of trail mix 20% raisins
Answer:
The length of AB is 4.33012701892
Step-by-step explanation:
1. You find 10*sin(60 degrees), because sin(60 degrees) = x/CT, and CT = 10. That means that sin(60 degrees) = x/10. You multiply by 10 on both sides, which would mean that x = 10sin(60 degrees) and that AT = 8.66025403784 because x is AT.
2. Then, because the relation between AT and AB and Angle T is sine, you use cosine to find x. If you do that, you find that the equation is sin(30 degrees) = x/8.66025403784. That means that 8.66025403784*sin(30 degrees) = x. If you calculate that, you find that x = 4.33012701892, and AB is x.
Answer:
what is the image and you said
Step-by-step explanation:
i am ready to help you
As per the given question, the expression of the function 
is as:
Now, as per the definition of zeros, the zero is that value of x which when plugged into the function should make the function zero (it is also called "making the function vanish"). <u>In our case, plugging in "zero values" of x should make the numerator zero without making the denominator zero.</u> Now, if we plug in the given values of x, which are x=-1, x=2 and x=4 in the function we see that the <u>numerator does not become a zero but the denominator does</u>.
Thus, x=-1, x=2 and x=4 are not the zeros of the function and therefore, Sue is wrong. However, we do have discontinuities at the aforementioned values of x because the denominator becomes a zero at those points and as per the definition of a discontinuity the denominator should be a zero at that point. Therefore, Ed is correct.
