First find the mean (sum divided by number of values)
4+5+8+10+15=42
42/5=8.4
Then find the difference between each of the numbers and the mean.
4.4, 3.4, 0.4, 1.6, 6.6
Then find the mean of those values.
4.4+3.4+0.4+1.6+6.6=16.4
16.4/5=3.28
Final answer: 3.28
Answer: x=6
The two angles shown in each are complementary because they add up to 90°.
10 & 12 would be supplementary to one another because they would add up to 180°.
Step-by-step explanation:
We know that on both 10 & 12 the angles add up to equal 90° so...
10. 8x+7x=90
15x=90
x=6
12. it's the same in pic as 10
The two angles shown in each are complementary because they add up to 90°.
10 & 12 would be supplementary to one another because they would add up to 180°.
Hi GlaxyCraft4991,
Solution:
−12x − 0.4 > 0.2 (36.5x + 80) − 55
−12x − 0.4 > 7.3x − 39
−12x − 0.4 − 7.3x > 7.3x − 39 − 7.3x
−19.3x − 0.4 > −39
−19.3x − 0.4 + 0.4 > −39 + 0.4
−19.3x > −38.6
−19.3x/19.3 > −38.6/19.3
x < 2
Correct Answer:
x < 2
Answer:
a)what was concluded is spurious
b) what was concluded could betrue
Step-by-step explanation:
a) Considering the number in Michigan, there is higher number of crimes but considering the population in Minnesota, the population is much less than Michigan, considering the crime the crimes per capital with the population size, Therefore Minnesota could have more crimes than Michigan's so, The conclusion is not true.
b)There is reduction of crimes from 1991 to 2001, so it can be assumed that the population has increased over the times, therefore, the per capita number of crimes decreased.
Given:
A driver is below the surface of the water at - 15m. he dives down by 6m, then rises 4m.
To find:
The current location of the driver.
Solution:
In this problem, negative sign is used for downward direction or the distance below the surface of the water.
Initial location = -15 m
Dives down by 6m, it means - 6m, then rises 4m, it means 4 m.
Now, the current location is



Therefore, the correct location of the driver is at -17 m it means her is 17 m below the surface of the water.