Answer:
State A had approximately 3,362 more earthquakes than State B
Step-by-step explanation:
Let
x-----> the number of earthquakes during a given time span
y ----> the land area affected
z----> seismic activity density of a region
step 1
Find the number of earthquakes during a given time span of State A
we know that
z = x/y
we have
z = 0.0299
y = 163,696mi^2
substitute and solve for x
0.0299 = x/163,696
x = 0.0299 x (163,696) = 4,895\earthquakes
Step 2
Find the number of earthquakes during a given time span of State B
we know that
z = x/y
we have
z=0.1402
y=10,931\ mi^2
substitute and solve for x
0.1402 = x/10,931
x = 0.0299 x (163,696) = 4,895\earthquakes
step 3
Compare the number of earthquakes both states
State A ----> 4,895\ earthquakes
State B ----> 1,533\ earthquakes
Find the difference
4,895 - 1,533 = 3,362\earthquakes
therefore
State A had approximately 3,362 more earthquakes than State B