1/8(-8c +16) - 1/3(6+3c)

Been stuck on these last 2 questions. can anybody help? thanks in advance!

Maurinko [17]

The equation that passes through the point (7, -2) and (11, 5) is y = 4/7x - 9

Equation of the line:

The standard form of the equation of the line is written as

y = mx + b

here

x and y represents the coordinates of the equation

m refers the slope of the equation

b refers the y intercept of the equation

Given,

Here we have the points (7, -2) and (11, 5).

Now we have to find the equation that passes through this points.

If you want to find the equation of the line, we have to find the slope and the intercept of the line.

The slope of the line is calculated by using the given point (7, -2) and (11, 5),

=> m = (11 - 7) / ( 5 - (-2))

=> m = 4/7

Now, we have to use the slope and the point (11, 5) to find the value of y intercept of the equation,

=> 5 = (4/7) (11) + b

=> 35 = 44 + b

=> b = -9

Therefore, the equation that passes through the points is y = 4/7x - 9

To know more about equation of the line here.

brainly.com/question/21511618

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4 0

1 year ago

Write 534 in two different ways

Darya [45]

if ur talking about like this then here

1. 354
2. 453 If this is what ur talking about i hope this helps :) :) :)

5 0

3 years ago

Read 2 more answers

Solve issuing Pythagorean theorem

Anna35 [415]

Step-by-step explanation:

(8x8) + (16x16) = 64+256 = 320

√320 = 17.9

8 0

3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

Use the Distributive Property to multiply.) -4x(x - 7)*

ad-work [718]

Answer:

-4x^2-28x

Step-by-step explanation:

Distribute

-4x(x) and -4x(-7)

-4x^2 and -28x

5 0

3 years ago

Read 2 more answers