Temporarily subdivide the given area into two parts: a large rectangle and a parallelogram. Find the areas of these two shapes separately and then combine them for the total area of the figure.
By counting squares on the graph, we see that the longest side of the rectangle is the hypotenuse of a triangle whose legs are 8 and 2. Applying the Pyth. Thm., we find that this length is √(8^2+2^2), or √68. Similarly, we find the the width of this rectangle is √(17). Thus, the area of the rectangle is √(17*68), or 34 square units.
This leaves the area of the parallelogram to be found. The length of one of the longer sides of the parallelogram is 6 and the width of the parallelogram is 1. Thus, the area of the parallelogram is A = 6(1) = 6 square units.
The total area of the given figure is then 34+6, or 40, square units.
Y=0.5x+800
in this equation the x is the weeks so for every week that goes by you would multiply 0.5 times that number then add the 800 original cm to get your answer (y)
Answer: D. a rotation followed by a translation
Answer
W=7
Explanation:
The formula for the perimeter for a rectangle is P = 2L + 2W
The formula for the area of a rectangle is A = LW
where L = length and W = width
P = 22 and A = 28
22 = 2L + 2W
28 = LW
Rewriting the 2nd equation L = 28/W
Substituting this into the first equation
22=2(28/W) + 2W
Reworking the equation to eliminate the denominator
22W = 2(28) + 2W2
22W = 56 + 2W2
and
2W2 - 22W + 56 = 0
Dividing by 2
W2 - 11W + 28 = 0
(W-7)(W-4)
Set each factor equal to 0 and solve each for 0
W = 4, W = 7
then W = 4
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Answer:
vertex = (1, - 9 )
Step-by-step explanation:
The equation of a parabola in vertex form is
f(x) = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Given
f(x) = x² - 2x - 8
To complete the square
add/ subtract ( half the coefficient of the x- term )² to x² - 2x
f(x) = x² + 2(- 1)x + 1 - 1 - 8
= (x - 1)² - 9 ← in vertex form
with vertex = (1, - 9 )
