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kolbaska11 [484]
3 years ago
9

22 points + brainliest! A fair die with sides labeled 1 through 6 is rolled two times. The values of the two rolls are added tog

ether. The sum is recorded as the outcome of a single trial of a random experiment. Compute the probability that the sum is 9.

Mathematics
2 answers:
murzikaleks [220]3 years ago
8 0

Answer:

P(9) = 1/9

Step-by-step explanation:

From the contingency table, we see that 9 appears 4 times out of the 36 possible outcomes, therefore the probability of having a sum of 9 is

P(9) = 4/36 = 1/9

ki77a [65]3 years ago
3 0

If the die is fair (and we will assume that all of them are), then each of these outcomes is equally likely. Since there are six possible outcomes, the probability of obtaining any side of the die is 1/6. The probability of rolling a 1 is 1/6, the probability of rolling a 2 is 1/6, and so on.

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A shop in the mall is 8 yards by 12 yards. How much would it cost to recarpet the shop with carpet that costs $2.69 per square y
valentinak56 [21]

Answer:

Step-by-step explanation:

You will first have to find the area to find the price of each square yard.

Area is 8*12 = 96. Multiply this by 2.69.

It will cost 258.24 dollars to recarpet the shop.

Let me know if this helped

7 0
2 years ago
Read 2 more answers
The old city park is rectangular. It has a length of 350 meters. It has a width of 125 meters. What is the perimeter, in meters,
Natali5045456 [20]

(350x2=700) + (125x2=250) 700+250=950 so the perimeter is 950 meters long I hope this helps!

5 0
3 years ago
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

3 0
3 years ago
I need help with the first part I will give brainliest
kaheart [24]

Answer:15 candy bars are solddd

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can you help me please?
gulaghasi [49]

Answer:

I think the answer is B, because the value does increase by one

6 0
3 years ago
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