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Klio2033 [76]
3 years ago
10

Find four geometric means between 25 and 800.

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0

Actually, you have to find four missed terms of geometrical sequence. Denote

a_1=25,\\ a_6=800

and r - ratio, then

a_2=a_1\cdot r=25r,\\a_3=a_1\cdot r^2=25r^2,\\a_4=a_1\cdot r^3=25r^3,\\a_5=a_1\cdot r^4=25r^4,\\a_6=a_1\cdot r^5=25r^5.

Since a_6=800, you have that 800=25r^5, then

r^5=\dfrac{800}{25} =32,\\r=2.

Now substitude r=2 in each of unknown 4 terms:

a_2=25\cdot 2=50,\\a_3=25\cdot 2^2=100,\\a_4=25\cdot 2^3=200,\\a_5=25\cdot 2^4=400.

Answer: four geometric means between 25 and 800 are 50, 100, 200, 400.

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Answer and Step-by-step explanation: <u>Standard</u> <u>form</u> of a quadratic equation is expressed as: y=ax²+bx+c, while <u>vertex</u> <u>form</u> is written as:

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