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andre [41]
4 years ago
5

How would you set it up?

Physics
1 answer:
Firdavs [7]4 years ago
5 0

Answer:

THE LAST OPTION

Explanation:

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A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the E
Sveta_85 [38]

Answer:

995 N

Explanation:

Weight of surface, w= 4000N

Gravitational constant, g, is taken as 9.81 hence mass, m of surface is W/g where W is weight of surface

m= 4000/9.81= 407.7472

Using radius of orbit of 6371km

The force of gravity of satellite in its orbit, F=\frac {GMm}{(2r)^{2}}=\frac {GMm}{4(r)^{2}}

Where G=6.67*10^{-11} and M=5.94*10^{24}

F=\frac {(6.67*10^{-11}*5.94*10^{24}*407.7472)}{4*({6.371*10^{6}m)}^{2}}

F= 995.01142 then rounded off

F=995N

6 0
3 years ago
Wave interactions
rewona [7]

Hi! I want to know this

6 0
3 years ago
Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/s through a horizontal tube with a 30mm diameter. wh
MariettaO [177]

The pressure drop in pascal is 3.824*10^4 Pascals.

To find the answer, we need to know about the Poiseuille's formula.

<h3>How to find the pressure drop in pascal?</h3>
  • We have the Poiseuille's formula,

                      Q=\frac{\pi Pr^4}{8\beta l}

where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, \beta is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.

  • It is given that,

                Q=8*10^{-6}m^3/s\\diameter=30mm, thus,\\r=15mm\\l=100m\\\beta =0.95

  • Thus, the pressure drop will be,

                P=\frac{8Q\beta l}{\pi r^4} =\frac{8*8*10^{-6}*0.95*100}{3.14*(15*10^{-3})^4} \\\\P=3.824*10^4Pascals.

Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4 Pascals.

Learn more about the Poiseuille's formula here:

brainly.com/question/13180459

#SPJ4

3 0
1 year ago
Figure shows three blocks that are being pulled along a smooth horizontal surface. The masses of the blocks
Eva8 [605]

Answer:

The pulling force F is 200 N

Explanation:

We note that the tension in a rope between two or three blocks is given by the relation;

Where we have;

m₁ → T₁ → m₂ → T₂ → m₃ → F

T_1 = \dfrac{m_1}{m_1 + m_2 + m_3} \times F

T_2 = \dfrac{m_1 + m_2}{m_1 + m_2 + m_3} \times F

m₁ = 2 kg

m₂ = 4 kg

m₃ = 4 kg

T₂ = 120 N

Therefore, by substitution, gives;

2 kg → T₁ → 4 kg → 120 N → 4 kg → F

120 \ N = \dfrac{2 \ kg + 4 \ kg}{2 \ kg+ 4 \ kg+ 4 \ kg} \times F = \dfrac{6 \ kg}{10 \ kg} \times F

F = 120 N × (10 kg)/(6 kg) = 200 N

The pulling force F = 200 N.

7 0
3 years ago
To ensure the greatest nutritional benefits, dietary guidelines suggest which of the following?
oee [108]
The answer would be D. Eating nutrient-dense foods
3 0
4 years ago
Read 2 more answers
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