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KiRa [710]
3 years ago
10

Is everyone lowkey turning goth?

Physics
2 answers:
iogann1982 [59]3 years ago
5 0

Answer:

it is marked by mystery and ambiguity. If to this fascination for creating tension is added a feeling of fear

Explanation:

do I help you

natulia [17]3 years ago
3 0

Answer:

Yeah it's the new trend lol it's kinda weird

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Which type of pollution occurs when small particles of soil are suspended in water?
vova2212 [387]
The type of pollution when small particles of soil are suspended in the water is called Suspended Matter Pollution.  <span>This type of pollution happens when soil enter the water and do not mix in with the water molecules.</span>
7 0
3 years ago
Read 2 more answers
A coin is dropped from a height of 188 meters. Neglecting air resistance, how much time (in seconds) was the coin in the air?
Marina CMI [18]

Answer:

t=6.19s

Explanation:

With a initial velocity is zero, kinematics equation is:

y=1/2*g*t^2

t=\sqrt{2y/g}=\sqrt{2*188/9.81}=6.19s

8 0
3 years ago
A stone is launched vertically upward from a cliff 384 ft above the ground at a speed of 80 ft divided by s. Its height above th
goldenfox [79]

Answer:

2.5 seconds

Explanation:

s(t) = -16t^2 + 80t + 384

for

0≤t≤8

First we differentiate s(t) to get s'(t)

s'(t) = -32t + 80

Let us then find the critical point; thus we will equate s'(t) to zero and then search for values where s'(t) is undefined

s'(t) = -32t + 80 = 0

t = 80/32

t = 2.5 sec

Let us evaluate s at the critical points and end points

s(0) = -16(0)^2 + 80(0) + 384 = 384

s(2.5) = -16(2.5)^2 + 80(2.5) + 384 = 684

s(8) = -16(8)^2 + 80(8) + 384 = 0

Thus, the stone attains it maximum height of 684ft at at t=2.5s

3 0
3 years ago
Solve this physics for me <br>please with steps<br>​
Mars2501 [29]

Answer:

The answers are located in each of the explanations showed below

Explanation:

a)

(i) Surface Tension: The tensile force that causes this tension acts parallel to the surface and is due to the forces of attraction between the molecules of the liquid. The magnitude of this force per unit of length is called surface tension.

σ = F/l [N/m]

where:

F = force [N]

l = length [m]

σ = Surface Tension [N/m]

(ii) Frequency is the number of repetitions per unit of time of any periodic event.

f = 1/T [1/s] or [s^-1] or [Hz]

where:

T = period [s] or [seconds]

f = frecuency [Hz] or [hertz]

(iii) Each of the units will be shown for each variable

v = velocity [m/s]

a = accelertion [m/s^2]

s = displacement [m]

[\frac{m}{s} ]^{2} =[\frac{m}{s} ]^{2} + 2* [\frac{m}{s^{2} } ]*[m]\\

[\frac{m^2}{s^2} ] =[\frac{m^2}{s^2} ] +  [\frac{m^{2} }{s^{2} } ]

[\frac{m^2}{s^2} ]

b) To find the velocity we must derivate the function X with respect to t because this derivate will give us the equation for the velocity, it means:

v=\frac{dx}{dt} \\v = 0.75*2*t+5*t

(i) X = 0.75*t^{2} +5*t+1\\X = 0.75*(4)^{2} +5*(4)+1\\X = 33 [m]

ii) replacing in the derivated equation.

v=1.5*(4)+5\\v=11[m/s]

iii) the average velocity is defined by the expresion v = x/t

v = \frac{x-x_{0} }{t-t_{0} } \\

x_{0}=0.75(2)^{2}+5(2)+1 \\ x_{0}=14[m]\\x=0.75(7)^{2}+5(7)+1\\x=72.75[m]\\t = 7 [s]t0= 2[s]Now replacing:[tex]v_{prom} = \frac{72.75-14}{7-2} \\v_{prom} = 11.75 [m/s]

2

a) Pascal's principle or Pascal's law, where the pressure exerted on an incompressible fluid and in balance within a container of indeformable walls is transmitted with equal intensity in all directions and at all points of the fluid.

Therefore:

P1 = pressure at point 1.

P2 = pressure at point 2.

P1 = F1/A1

P2= F2/A2

\frac{F_{1} }{A_{1} }=\frac{F_{2}}{A_{2} }  \\F_{1}=A_{1}*(\frac{F_{2}}{A_{2} })

b) One of the applications of the surface tension is the <u>capillarity</u> this is a property of liquids that depends on their surface tension (which, in turn, depends on the cohesion or intermolecular force of the liquid), which gives them the ability to climb or descend through a capillary tube.

Other examples of surface tension:

The mosquitoes that can sit on the water.

A clip on the water.

Some leaves that remain floating on the surface.

Some soaps and detergents on the water.

5 0
3 years ago
An ethernet cable is 3.80 m long and has a mass of 0.210 kg. A transverse pulse is produced by plucking one end of the taut cabl
Tasya [4]

Answer:

T=94.54N

Explanation:

The tension in a cable is given by:

T=\mu v^2(1)

Where \mu is the mass density of the cable and v is the speed of the cable's pulse. These values are defined as:

\mu=\frac{m}{L}(2)\\v=\frac{d}{t}

The pulse makes four trips down and back along the cable, so d=4(2L)

v=\frac{8L}{t}(3)

Replacing (2) and (3) in (1), we calculate the tension in the cable:

T=\frac{m}{L}(\frac{8L}{t})^2\\T=\frac{64mL}{t^2}\\T=\frac{64(0.21kg(3.80m))}{(0.735s)^2}\\T=94.54N

3 0
3 years ago
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