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Tanzania [10]
4 years ago
10

To ensure the greatest nutritional benefits, dietary guidelines suggest which of the following?

Physics
2 answers:
Flura [38]4 years ago
4 0
D. Eating nutrient-dense foods.
oee [108]4 years ago
3 0
The answer would be D. Eating nutrient-dense foods
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A 7 cm thick and 20 cm long wedge is used to pierce a 3cm long log of diameter 20cm what is the velocity ratio of the wedge
stiks02 [169]

Answer:

The velocity ratio of the wedge is 0.15

Explanation:

Use the following formula to calculate the velocity ratio

Velocity Ratio = Distance Moved by effort / Distance moved by Load

Where

Distance Moved by effort = 3cm

Distance moved by Load = 20 cm

Placing values in the formula

Velocity Ratio = 3cm / 20 cm

Velocity Ratio = 0.15

6 0
3 years ago
How much force is needed to accelerate a 3 kg skateboard at 5 m/s2
Umnica [9.8K]

The problem is fairly simple if you use the formula.

Formula: Force = (mass) x (acceleration)

3 x 5 = 15 newtons

Note: 3 kg is the mass of the skateboard, and 5 m/s2 is the acceleration.

Answer: 15 newtons

3 0
3 years ago
Read 2 more answers
Un Esquiador Inicia un Salto Horizontal con una velocidad Inicial de 25 m/s. La Altura al Final de la Rampa es de 80 m del punto
Evgesh-ka [11]

Responder:

Explicación:

Para que podamos calcular el tiempo que le tomará al esquiador permanecer en el aire, encontraremos el tiempo de vuelo como se muestra;

T = 2Usin theta / 2

theta = 90 grados

U = 25 m / s

T = 25sin90 / 2 (9,8)

T = 25 / 19,62

T = 1,27 segundos

Por lo tanto, los cielos usarán 1.27 segundos en el aire.

La distancia horizontal es el rango;

Rango R = U√2H / g

R = 25√2 (80) /9,8

R = 25√160 / 9,8

R = 25 * √16,326

R = 25 * 4.04

R = 101,02 m

Por tanto, la distancia horizontal recorrida por el esquiador es 101,02 m

5 0
3 years ago
A 250 N force pulls on a box horizontally to the right. The box is moving at constant speed.
lana66690 [7]

Answer:

its 34

Explanation:

3 0
3 years ago
A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the ground. How far, in meters, from the deck doe
Vesna [10]

Answer:

2.605m

Explanation:

Using the formula for calculating Range (distance travelled in horizontal direction)

Range R = U√2H/g

U is the speed = 4.8m/s

H is the maximum height = ?

g is the acc due to gravity = 9.8m/s²

R = 3.5m

Substitute into the formula and get H

3.5 = 4.8√2H/9.8

3.5/4.8 = √2H/9.8

0.7292 = √2H/9.8

square both sides

0.7292² = 2H/9.8

2H = 0.7292² * 9.8

2H = 5.21

H = 5.21/2

H = 2.605m

Hence the height of the ball from the ground is 2.605m

7 0
3 years ago
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