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liberstina [14]
2 years ago
9

A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of the E

arth to the surface. If the satellite had a weight at the surface of 4000 N, what is the force of gravity (weight) of the satellite when it is in its orbit? Give your answer in newtons, N.
Physics
1 answer:
Sveta_85 [38]2 years ago
6 0

Answer:

995 N

Explanation:

Weight of surface, w= 4000N

Gravitational constant, g, is taken as 9.81 hence mass, m of surface is W/g where W is weight of surface

m= 4000/9.81= 407.7472

Using radius of orbit of 6371km

The force of gravity of satellite in its orbit, F=\frac {GMm}{(2r)^{2}}=\frac {GMm}{4(r)^{2}}

Where G=6.67*10^{-11} and M=5.94*10^{24}

F=\frac {(6.67*10^{-11}*5.94*10^{24}*407.7472)}{4*({6.371*10^{6}m)}^{2}}

F= 995.01142 then rounded off

F=995N

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<span>Answer: The acceleration of 10 kg object is greater than that of 18 kg object.

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Let's find the acceleration for both 10 kg and 18 kg objects!
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