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Elena L [17]
3 years ago
10

The answer to d+n=25 and d+n=2.10

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

Answer:

1250

Step-by-step explanation:

d = 12

n = 50

add

1250

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the second answer chose is the right answer chose

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If it is 10:00 am at your location when it is noon along the prime meridian, what is your longitude
Rudiy27
Every 15 degrees along the line of longitude is equivalent to a time difference of 1 hour.

Given that <span>it is 10:00 am at your location when it is noon along the prime meridian</span>, this means that you are 2 hours behind the prime meridian.

The prime meridian is 0 degrees and you are 2 x 15 = 30 degrees west of the prime meridian.

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4 0
3 years ago
Please help!! <br> Solve the system using an augmented matrix. Show all work
marishachu [46]

Answer:

<em>The solution of the system is:  x=2, y=5</em>

Step-by-step explanation:

The given system of equations is.......

-x-3y=-17\\ \\ 2x-6y=-26

So, the augmented matrix will be:   \left[\begin{array}{cccc}-1&-3&|&-17\\2&-6&|&-26\\\end{array}\right]

Now, we will transform the augmented matrix to the reduced row echelon form using row operations.

<u>Row operation 1 :</u>  Multiply the 1st row by -1. So..........

\left[\begin{array}{cccc}1&3&|&17\\2&-6&|&-26\\\end{array}\right]

<u>Row operation 2:</u>  Add -2 times the 1st row to the 2nd row. So.......

\left[\begin{array}{cccc}1&3&|&17\\0&-12&|&-60\\\end{array}\right]

<u>Row operation 3:</u>  Multiply the 2nd row by -\frac{1}{12}. So.......

\left[\begin{array}{cccc}1&3&|&17\\0&1&|&5\\\end{array}\right]

<u>Row operation 4:</u>  Add -3 times the 2nd row to the 1st row. So........

\left[\begin{array}{cccc}1&0&|&2\\0&1&|&5\\\end{array}\right]

Now, from this reduced row echelon form of the augmented matrix, we can get that x=2 and y=5

So, the solution of the system is:  x=2, y=5

8 0
3 years ago
PLS HELP <br> WILL GIVE BRAINLIEST
alexandr1967 [171]

answer:

(-7; -5)

step by step

3 0
2 years ago
Please help me!!! 30 minutes left
Lesechka [4]

Option D:

\frac{25 a^{9} b^{10} }{6 } is equivalent to the given expression.

Solution:

Given expression:

$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}

To find which expression is equivalent to the given expression.

$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}

Using exponent rule: (ab)^m=a^mb^m

    $=\frac{5^3 a^3 b^{3}}{30 a^{-6} b^{-7}}

Using exponent rule: \frac{1}{a^{m}}=a^{-m}, \quad \frac{1}{a^{-m}}=a^{m}

     $=\frac{125 a^3 b^{3}a^{6} b^{7}}{30 }

     $=\frac{125 a^3 a^{6} b^{3} b^{7}}{30 }

Using exponent rule: a^{m} \cdot a^{n}=a^{m+n}

     $=\frac{125 a^{3+6} b^{3+7} }{30 }

    $=\frac{125 a^{9} b^{10} }{30 }

Divide both numerator and denominator by the common factor 5.

    $=\frac{25 a^{9} b^{10} }{6 }

$\frac{(5 a b)^{3}}{30 a^{-6} b^{-7}}=\frac{25 a^{9} b^{10} }{6 }

Therefore,  \frac{25 a^{9} b^{10} }{6 } is equivalent to the given expression.

Hence Option D is the correct answer.

4 0
3 years ago
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