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nikdorinn [45]
3 years ago
11

Which point is in Quadrant IV?

Mathematics
2 answers:
alukav5142 [94]3 years ago
8 0

Answer:

h

Step-by-step explanation:

bottom right quadrant is IV

sattari [20]3 years ago
3 0

Answer:

1,1 or -1,3

Step-by-step explanation:

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HELP ME!!! ITS DUE TOMMOROW!! Find the largest value of $r$ such that $6r^2+7r+8=6$.
Alex787 [66]
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
6r^2 + 7r + 8 = 6
6r^2 + 7r + 2 = 0

Now this one is difficult to factor so i will use quadratic equation:
[-b (+-) sqrt (b^2 - 4ac)] / (2a)

we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c

so
[-7 (+-) sqrt (7^2 -(4)(6)(2)] / (2) (6)
[-7 (+-) sqrt (49 - 48)] / 12
[-7 (+-) 1] /12

split into the + and - for 2 answers
(-7 + 1) / 12
-6/12
-1/2

And
(-7 -1) /12
-8 / 12
-2/3

those are.the 2 answers

But but it says largest so -1/2
4 0
3 years ago
Read 2 more answers
What does X equal. If the area is 12 units.
Ray Of Light [21]
Im not sure, you didn't put a question
3 0
3 years ago
My cats thoughts while she is just laying there with her face in my clothes:
nata0808 [166]

Answer:

ADORABLE!!

Step-by-step explanation:

7 0
3 years ago
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The Tour de France is a bike race around the country of France. The bike race is a three week race that covers approximately 2,2
valentinak56 [21]

Answer:

Approximately 54.54% of race happened in the first week.

Step-by-step explanation:

We are given the following in the question:

Length of bike race in three weeks = 2,200 miles

Race covered in first week = 1,200 miles

Percentage of race covered in first week =

=\dfrac{\text{Race covered in first week}}{\text{Total length of race}}\times 100\%\\\\=\dfrac{1200}{2200}\times 100\%\\\\=54.54\%

Thus, approximately 54.54% of race happened in the first week.

4 0
3 years ago
1. Triangle STU with vertices S(-4, 2) T(5, -1),
Alexus [3.1K]

Answer:

S’ (-5,-3)

T’ (4,-6)

U’ (-3,-7)

Step-by-step explanation:

Basically, we want to apply the given transformation rule of the axes to get the coordinates of the images

The rule is that we subtract 1 from the x-coordinates and also subtract 5 from the y-coordinates

Thus, we proceed as follows;

S’ = (-4-1, 2-5) = (-5,-3)

T’ = (5-1, -1-5) = (4,-6)

U’ = (-2-1,-2-5) = (-3,-7)

4 0
2 years ago
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