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3 years ago

Explain the process of adaptive radiation. Give an example.

Physics

1 answer:

ivanzaharov [21]3 years ago

7 0

Answer:

Adaptive radiation usually refers to the diversification of living species that are evolved from a common ancestor. There occur changes and modifications in the ecological system, due to which the species can adapt to the changing environment with the available resources. It also modifies the ways in which the existing species interacts with the surrounding environment. Here, the species select the ecological niches naturally.

A plant named 'silver sword' that is commonly found in Hawaii, and the appearance and diversification of mammals after the extinction of dinosaurs by the end of Cretaceous, are two examples of adaptive radiation.

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Suppose the price elasticity of supply for gasoline in the short run is estimated to be 0.4. Due to an unexpected surge in the d

netineya [11]

Answer:

increase by 8 percent

Explanation:

<em>Price elasticity of supply of a product is the degree of responsiveness of supply of that product to a change in price.</em> Simply put:

Price Elasticity of supply = change in quantity supply/ change in price.

In this case, price elasticity of supply of gasoline = 0.4

Percentage price increase = 20 percent.

Hence,

0.4 = change in supply/20

Change in supply = 20 x 0.4 = 8 percent

<em>Therefore, the quantity supply of gasoline will increase by 8 percent</em>

5 0

3 years ago

Jaclyn plays singles for South's varsity tennis team. During the match against North, Jaclyn won the sudden death tiebreaker poi

Nataly [62]

Answer

given,

mass of ball, m = 57.5 g = 0.0575 kg

velocity of ball northward,v = 26.7 m/s

mass of racket, M = 331 g = 0.331 Kg

velocity of the ball after collision,v' = 29.5 m/s

a) momentum of ball before collision

P₁ = m v

P₁ = 0.0575 x 26.7

P₁ = 1.535 kg.m/s

b) momentum of ball after collision

P₂ = m v'

P₂ = 0.0575 x (-29.5)

P₂ = -1.696 kg.m/s

c) change in momentum

Δ P = P₂ - P₁

Δ P = -1.696 -1.535

Δ P = -3.231 kg.m/s

d) using conservation of momentum

initial speed of racket = 0 m/s

M u + m v = Mu' + m v

M x 0 + 0.0575 x 26.7 = 0.331 x u' + 0.0575 x (-29.5)

0.331 u' = 3.232

u' = 9.76 m/s

change in velocity of the racket is equal to 9.76 m/s

5 0

4 years ago

11. A wire made of silver has coefficient of linear expansion, 29x10-6/k and length of 10m. A square metal plate made of such si

Levart [38]

By using the coefficient of linear expansion, the increase in the length of the metal plate is by 0.015m and in the area is by 0.3074 $m^2$ .

The rate of change in length of a metal per degree change in temperature is known as the coefficient of linear expansion.

Given:

Coefficient of linear expansion, α = 29 x $10^-^6$ /k

Length, L1 = 10m

T1 = 25℃

T2 = 78℃

ΔT = 78 – 25 = 53℃

To find:

Change in length (ΔL) and area (ΔA) of metal plate = ?

Formula:

ΔL = α L1 ΔT

ΔA = A1 2 α ΔT

Calculations:

ΔL = 29 x $10^-^6$ x 10 x 53

ΔL = 0.01537m

ΔA = 100 x 2 x 29 x $10^-^6$ x 53

ΔA = 0.3074 $m^2$

A2 = 100.3074 $m^2$

Result:

The increase in the length and area is by 0.015m and 0.3074 $m^2$ respectively.

Learn more about Coefficient of linear expansion of metals here:

brainly.com/question/14780533

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5 0

1 year ago

The diagram shows the Earth rotating on it's axis. The two star symbols show different locations on the surface... What would th

rewona [7]

It would look like Sunset

8 0

3 years ago

Read 2 more answers

Ship A is located 4.2 km north and 2.7 km east of ship B. Ship A has a velocity of 22 km/h toward the south and ship B has a vel

kotykmax [81]

Answer:

(a) The x-component of velocity is 31.55 km/h

(b) The y-component of velocity is 44.92 km/hr

Solution:

As per the solution:

The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.

Velocity of ship A, $\vec{u_{A}}$ = 22 km/h towards South = $- 22\hat{j}$

Velocity of ship B, $\vec{u_{B}}$ = 39 km/h Towards North east at an angle of $36^{\circ}$ = $\vec{u_{B}} = 39sin36^{\circ} \hat{j}$

Now, the velocity of ship A relative to ship B:

$\vec{u_{AB}} = \vec{u_{A}} - \vec{u_{B}}$

$\vec{u_{A}} = - 22\hat{j}$

$\vec{u_{B}} = 39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}$

Now,

$\vec{u_{AB}} = - 22\hat{j} +39cos36^{\circ} \hat{i} - 39sin36^{\circ} \hat{j}$

$\vec{u_{AB}} = 31.55\hat{i} - 44.92\hat{j}$

4 0

3 years ago