Answer:
The rate at which water leaking is gal/min.
Step-by-step explanation:
Given:
A large container holds 8 gallons of water.
After 56 minutes the container only has 1 gallon of water left.
Now, to find at what rate is the water leaking.
So, water leaked from the container = 8 gallons - 1 gallon = 7 gallons.
Time taken for leakage = 56 minutes.
<em>Now, to get the rate:</em>
The rate = gal/min.
Therefore, the rate at which water is leaking is gal/min.
Answer:
D
Step-by-step explanation:
Using the Cosine rule to find AC
AC² = BC² + AB² - (2 × BC × AB × cosB )
= 18² + 12² - ( 2 × 18 × 12 × cos75° )
= 324 + 144 - 432cos75°
= 468 - 111.8
= 356.2 ( take the square root of both sides )
AC = ≈ 18.9
-----------------------------------------
Using the Sine rule to find ∠ A
=
( cross- multiply )
18.9 sinA = 18 sin75° ( divide both sides by 18.9 )
sinA = , then
∠ A = (
) ≈ 66.9°
Answer:
Step-by-step explanation:
