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3 years ago

Which statement about this figure is true

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

6 0

Answer:

D: It has reflectional symmetry with one line of symmetry

Step-by-step explanation:

The reason D is the answer is because, the tree has the same sides and if you put a line in the middle of the tree it is identical to the other side.

otez555 [7]3 years ago

5 0

Answer:

Its Either B or C

Step-by-step explanation:

It does have 180 degree angles

It has point symmetry

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Number 14 please help 10 points no links pleAse

marshall27 [118]

Answer:

Step-by-step explanation:

5 0

2 years ago

If we add 9 tens 5 hundreds and 3 ones then the result is?

ioda

Answer:

9 tens = 90

5 hundreds = 500

3 ones = 3

on adding them we get, 500 + 90 + 3 = 593

6 0

1 year ago

Read 2 more answers

What is the result when 4x3 + 19x2 + 29x + 14 is divided by 4x + 7?

Sergio039 [100]

Step-by-step explanation:

4x³ + 19x² + 29x + 14

= (4x³ + 7x²) + (12x² + 21x) + (8x + 14)

= x²(4x + 7) + 3x(4x + 7) + 2(4x + 7).

= (x² + 3x + 2)(4x + 7).

Hence 4x³ + 19x² + 29x + 14 divided by 4x + 7 is x² + 3x + 2 or (x + 1)(x + 2).

3 0

2 years ago

Read 2 more answers

Help please not sure of this one

shutvik [7]

Answer:

True, A

Step-by-step explanation:

If you sum two different sides of a traingle it must be greater than the remaining one

We can test that by adding the two smallest sides

1+8=9

9 is obviously greater than 8, so the answer is: true

8 0

2 years ago

Read 2 more answers

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

2 years ago