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kumpel [21]
3 years ago
15

An object is 1.0 cm tall and its erect image is 5.0 cm tall. what is the exact magnification?

Physics
1 answer:
ikadub [295]3 years ago
7 0
The exact magnification of the objects is calculated by dividing the cinema. We calculate it by diving the erect image size by the object size. From the given above, we find the exact magnification by dividing 5.0 cm by 1.0 cm. Thus, the answer would be 5. 
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Noble Gases do not readily form compounds because they ___ chemically stable with 8 valence electrons
azamat

Answer : Noble Gases do not readily form compounds because they are chemically stable with 8 valence electrons.

Explanation :

Noble gases are the chemical elements that are present in group 18 in the periodic table.

The elements are helium, neon, argon, krypton, xenon and radon.

They are chemically most stable except helium due to having the maximum number of 8 valence electrons can hold their outermost shell that means they have a complete octet.

They are rarely reacts with other elements to form compounds by gaining or losing electrons since they are already chemically stable.

Hence, the noble Gases do not readily form compounds because they are chemically stable with 8 valence electrons.

8 0
3 years ago
a watermelon is balanced by a dog, a pumpkin, a flowerpot, and a baseball as shown below. Is the weight of the watermelon equal
alukav5142 [94]

Answer:

pumpkin

Explanation:

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3 years ago
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crimeas [40]
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3 0
3 years ago
An object of mass m is hung from a spring and set into oscillation. The period of the oscillation is measured and recorded as T.
sergejj [24]

Answer:\sqrt{2}T

Explanation:

Given

object of mass m is suspended from spring and set in oscillation with time Period T

We know Time period of a mass in oscillation is given by

T=2\pi \sqrt{\frac{m}{k}}

where k=spring constant

When mass m is replaced by a mass of 2 m time period is given by

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T'=\sqrt{2}\times 2\pi \sqrt{\frac{m}{k}}

T'=\sqrt{2}T

i.e. New time period becomes \sqrt{2} times of previous one

                         

7 0
3 years ago
Suppose a large truck on a hydraulic lift exerts 7,000 N of force on a piston with an area of 0.4 m2. The piston can only suppor
uysha [10]

Pressure is the amount of force per unit area. In formula it is,

P = F ÷ A

P = 7000 N ÷ 0.4 m2

P = 17,500 N/m2

The amount of pressure the truck exerts on the piston is 17,500 N/m2

7 0
3 years ago
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